Convert string of hex to array of dec

I need to convert a string of hexidecimal numbers to an array of dec numbers. The string can potentially contain incomplete hex numbers at the beginning and end of the string. See examples below. I'm trying to use this in a data acquisition setup...so execution time could be a factor.
Input String Examples ('/r' = carriage returns:
s1 = '0001h/r0002h/r0003h/r';
s2 = '4h/r0001h/r0002h/r0003h/r00';
Output Desired:
a1 = [1,2,3]
a2 = [1,2,3]

 Risposta accettata

s1 = '0001h/r0002h/r0003h/r';
s1 = '4h/r0001h/r0002h/r0003h/r00';
str=regexp(s1,'h/r','split');
Ind=cellfun(@length,str);
str=str(Ind==4);
num=hex2dec(str);

2 Commenti

Worked perfectly. Thanks.
Jan
Jan il 17 Ago 2011
cellfun('prodofsize', str) is faster than cellfun(@length, str).

Accedi per commentare.

Più risposte (1)

Jan
Jan il 17 Ago 2011
A simpler method, which is substantially faster:
s1 = '0001h/r0002h/r0003h/r';
a1 = sscanf(a, '%xh/r')
But this does not reject the 4 of the string '4h/r0001h/r0002h/r0003h/r00'!
If you mean \r instead /r:
s1 = sprintf('0001h\r0002h\r0003h\r');
a1 = sscanf(a, '%xh')

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