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draw two 3D curve but can't hold them in one figure

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Gary
Gary il 20 Ago 2014
Commentato: Image Analyst il 20 Ago 2014
the first curve is a solution of a differential equation
function dy=eq3(t,y)
dy=zeros(3,1);
dy(1)=-680*(y(1)-100000)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
dy(2)=-680*(y(2)-340*t)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
dy(3)=-680*(y(3)-10000)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
end
and the second one is a line in a 3Dspace
[t,y]=ode45('eq3',[0:0.01:202],[0,0,0]);
plot3(y(:,1),y(:,2),y(:,3))
grid on
hold on
T=0:0.5:200;
X=100000;
Y=340*T;
Z=10000;
plot3(X,Y,Z,'r')
xlabel('x轴')
ylabel('y轴')
zlabel('z轴')
but they don't show up together

Risposte (1)

Aniruddha Katre
Aniruddha Katre il 20 Ago 2014
The reason why the second plot does not show up is because the variables "X" and "Z" are both scalars while "Y" is a vector. You can just convert "X" and "Z" to vectors of the same dimensions as "Y" and the plot should work. Assuming you want to keep "X" and "Z" constant, you can convert them to vectors in the following manner:
X=100000*ones(length(T),1);
Z=10000*ones(length(T),1);
  2 Commenti
Image Analyst
Image Analyst il 20 Ago 2014
You can "thank" him by officially "Accepting" his answer. It will give him reputation points.

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