how to define functions with variable values

57 visualizzazioni (ultimi 30 giorni)
Hello,
I'm trying to define a function x1=-c1/b1*x2+d1/b1, where b1,c1,d1 are defined, but x2 should be kept as a variable. Here's how it all looks at the end

Risposta accettata

Star Strider
Star Strider il 21 Ago 2014
Modificato: Star Strider il 21 Ago 2014
You can do that with Anonymous Functions:
x1 = @(x2,b1,c1,d1) -c1./b1.*x2+d1./b1;
if you want to include all the constants as arguments,
or:
x1 = @(x2) -c1./b1.*x2+d1./b1;
if you want to pick the constants up automatically from the workspace.
  2 Commenti
John
John il 23 Ago 2014
Wow! That was quick. It only took you 7 minutes to answer, this other program that I've been using has a way slower community. The anonymous function works great. Though before posting, I tried searching for a similar post and in my findings encountered the anonymous function, without your help I couldn't properly understand how to apply it to my code. Thanks a million!
Star Strider
Star Strider il 23 Ago 2014
Modificato: Star Strider il 23 Ago 2014
My pleasure!
There are some truly brilliant people here. (I have my areas of expertise, but nothing to match others like Roger Stafford, Azzi Abdelmalek, Andrei Bobrov, Cedric Wannaz, and others. MATLAB staffers also appear here from time to time to provide detailed Answers the rest of us cannot.) Stay here if you need help. If you ask your Questions clearly, you will get clear Answers.
Also, contribute your own Answers as you gain expertise.
Apologise for the delay this time — GMT-6 here.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Characters and Strings in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by