Simulink

Why the integration of a sin() function, with the integrator block of simulink, doesn't give a waveform of -cos()??

Answer 1

[Grzegorz Knor]

What is your initial condition? Maybe 0?

In this case should be -1.

Integrator

[Grzegorz Knor]

hint: Initial condition you could set in Parameters and Dialog Box.

[Paulo Silva]

Good answer, having initial condition -1 instead of 0 solves the problem, +1 vote

Answer 2

[Fabio]

Thanks Grzegorz,

   I can see a cosine waveform but there is a peak upper than 1(almost 6), when the sine has an amplitude of 1. Do you know the reason of that behaviour?