Function Approximation and Interpolation

17 visualizzazioni (ultimi 30 giorni)
Given: f(x) = exp(-x^2) on the interval [-1; 1].
Need to:
  1. Approximate f(x) by a 9-degree monomial basis polynomial interpolant with equidistant nodes. Proceed as follows:
1.1. create a vector x containing the n = 9 interpolation nodes.
1.2. use the function 'vander' to create the interpolation matrix G.
1.3. compute yi = f(xi) at the n interpolation nodes.
1.4. compute the n basis coefficients c.
2. Evaluate the accuracy of the interpolant, say f1, as follows:
2.1. Use the Matlab function 'polyval' to evaluate f1 for 100 evenly distributed points on [-1; 1].
2.2. Compare these interpolated values with the 'true' values of f.
2.3. Plot the approximation error.
So far, could this. But no idea whether they are correct or not. Don't even understand what should do in 2.2 and 2.3
f = @(x) exp(-x.^2);
n = 9;
y = linspace(-1, 1, n);
z = [];
for i = 1:length(y)
z(i) = feval(f,y(i));
end
v = fliplr(vander(y));
a = v\z';
b = a(end:-1:1)';
%5
c = linspace(-1,1);
d = polyval(b, c);
p = polyfit(c,d);

Risposta accettata

David Hill
David Hill il 11 Ott 2021
Something like this.
f = @(x) exp(-x.^2);
x = linspace(-1, 1, 9);
G=vander(x);
y=f(x);
c=G\y';
f1=@(x)polyval(c,x);
t=linspace(-1,1,100);
Error=(f(t)-f1(t))./f(t);
plot(t,Error)

Più risposte (0)

Categorie

Scopri di più su Interpolation in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by