generate column array with day in year number for each hour in a year

Dear,

i want a column array with length equal to hours in a year: 365d*24h = 8760

the content of the array should be the number of the day, corresponding with the hours, so:

1,1,1,1,1,..1,2,2...,2,3,3,...,3... - 365,365,...,365. (total length: 8760 values, number 1 should be repeated 24 times, then number 2 repeated 24 times, etc).

How to code this efficiently?

What i tried was a for-loop, but i want to use a more efficient way:

days = zeros(24,1);
all_days = days;
for i = 1:365-1 
    all_days = [all_days; days+i];
end

Answer 1

[KSSV]

r=repmat(0:364,24,1) ;
r=r(:);

[Mayk]

wow genius! i did know repmat, but i didn't know that using r=r(:); puts everything in one column!

r = r(:); % this converts matrix into a one column array

Answer 2

[Mayk]

using this improvement, my time to run this section of code decrease from:

Elapsed time is 0.002214 seconds.

to

Elapsed time is 0.000130 seconds.

thanks!

measured by puting 'tic' before code and 'toc' at end of code to measure time to run code.