Error in Bvp4c

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Priya M
Priya M il 23 Ott 2021
Risposto: MOSLI KARIM il 27 Nov 2023
I'm trying to run the following bvp4c MATLAB code, but keep running into an error:
please anyone find out my mistakes and correct me..
Thank you.

Risposta accettata

Jan
Jan il 23 Ott 2021
You define the variable beta on top of the code, but this does not mean, that it is known in all subfunctions. Pr, gamma and lam are not known inside also.
Either define the constants, where they are needed, or provide them using an anonymous function:
for gamma=0.0:0.25:1
sol = bvpinit(linspace(0,5,50),[0 0 0 0 0 0 0]);
fcn = @(t,y) bvpexam1(t, y, beta, gamma, lam, Pr);
sol1 = bvp4c(fcn, @bcexam1,sol);
...
end
function ysol = bvpexam1(t, y, beta, gamma, lam, Pr)
...
end
  5 Commenti
Jan
Jan il 27 Ott 2021
Modificato: Jan il 27 Ott 2021
f =@(x,y)[y(2);
...
(1/(1+E*y(6)-Pr*gamma*y(1)^2))*(-E*y(7)^2-Pr*y(1)*y(7)+Pr*gamma*y(1)*y(2)*y(7))];
% ^
There is a missing closing square bracket in your code. After adding it I get a result.
Priya M
Priya M il 28 Ott 2021
Thanx a lot sir....

Accedi per commentare.

Più risposte (1)

MOSLI KARIM
MOSLI KARIM il 27 Nov 2023
this code works function d
Pr=0.72;
beta=0.5;
lam=0.2;
E=0.5;
for gamma=0.0:0.25:1
sol = bvpinit(linspace(0,5,50),[0 0 0 0 0 0 0]);
sol1 = bvp4c(@bvpexam1, @bcexam1,sol);
x1 = sol1.x;
y1 = sol1.y;
figure (1)
plot(x1, y1(2,:));
hold on
figure (2)
plot(x1, y1(6,:));
hold on
z = y1(3,1);
p = y1(7,1)'
figure(3)
plot(gamma,y1(7,1),'-bo')
hold on
end
function res = bcexam1(y0, yinf)
res=[y0(1)-0;y0(2)-1;y0(4)-0;y0(6)-1;yinf(2)-0;yinf(4)-0;yinf(6)-0];
end
function ysol = bvpexam1(~,y)
yy1 = (1/(1-beta*y(1)^2))*(-y(1)*y(3)+y(2)^2-2*lam*(y(4)-beta*y(1)*y(5))-2*beta*y(1)*y(2)*y(3));
yy2 = (1/(1-beta*y(1)^2))*(-y(1)*y(5)+y(2)*y(4)+2*lam*(y(2)+beta*(y(2)^2-y(1)*y(3)+y(4)))-2*beta*y(1)*y(2)*y(5));
yy3 = (1/(1+E*y(6)-Pr*gamma*y(1)^2))*(-E*y(7)^2-Pr*y(1)*y(7)+Pr*gamma*y(1)*y(2)*y(7));
ysol = [y(2);y(3);yy1;y(5);yy2;y(7);yy3];
end

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