Azzera filtri
Azzera filtri

Extract data from a web page

19 visualizzazioni (ultimi 30 giorni)
Dimitrios Poulos
Dimitrios Poulos il 23 Ott 2021
Commentato: Image Analyst il 24 Ott 2021
I want to extract a specific number from a web page. To be more accurate the number 74. It is the cloud coverage from Windy page. This information exist in the following image at the tab elements but my code is extracting more ....general information(attachment). How I could extract this specific info from tab ''elements'' in chrome browser?
In the attachment there is my result from the following code but 74 does not exist. :-(
url = char(strcat({'https://www.windy.com/?clouds,2021-10-27-11,'},{MitraN},{','},{MitraE},{',8,d:picker'}));
options = weboptions('CertificateFilename','');
A1 = webread(url,options)

Risposte (1)

Image Analyst
Image Analyst il 23 Ott 2021
Try turning that imcomprehensible mess of XML into an organized structure with the attached function:
url = char(strcat({'https://www.windy.com/?clouds,2021-10-27-11,'},{MitraN},{','},{MitraE},{',8,d:picker'}));
options = weboptions('CertificateFilename','');
A1 = webread(url,options)
s = xml2struct(A1)
  2 Commenti
Image Analyst
Image Analyst il 24 Ott 2021
We can't run your code because you did not define MitraN and MitraE. Tell us what those should be. Give us code that can run!
Image Analyst
Image Analyst il 24 Ott 2021
Why do you think "74" should exist in the returned string?
When you right click on the page and say View Source do you see a 74?
url = char('https://www.windy.com/?clouds,2021-10-27-11,23.1283199987984,-16.0439653616218,8,d:picker');
options = weboptions('CertificateFilename','');
A1 = webread(url,options)
index = strfind(A1, '74')
for k = 1 : 50 : length(A1)
k2 = min(length(A1), k+49);
fprintf('%s\n', A1(k:k2));
end

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by