Crop an image using coordinate

53 visualizzazioni (ultimi 30 giorni)
hu
hu il 2 Ott 2014
Commentato: Image Analyst il 16 Mag 2022
Hi,
How can I crop an image by having the top left coordinate (X1,Y1) and bottom right (X2,Y2).
I2 = imcrop(im,[x1 y1 x2 y2])
does not seem to work?
Thanks
  3 Commenti
nisa sarfraz
nisa sarfraz il 14 Gen 2020
I=imread(images(1).name); %crop one to get rect
this line of code give error of index matrix dimension exeeds. kindly suggest some solution
Image Analyst
Image Analyst il 14 Gen 2020
Nisa, start a new question, and give the code that you used to load up your images structure (was it the dir function?). Your images structure is evidently empty, meaning it found not images.
filePattern = fullfile(pwd, '*.png');
images = dir(filePattern);
if isempty(images)
message = sprintf('No PNG images found in folder %s\n', pwd)
uiwait(errordlg(message))
return;
end
thisImage=imread(images(1).name);
imshow(thisImage)
% Crop one to get rect
croppedImage = imcrop(thisImage);

Accedi per commentare.

Risposta accettata

Image Analyst
Image Analyst il 2 Ott 2014
You used 151 instead of 115 in your width. Here, try this:
grayImage = imread('circuit.tif');
subplot(1,2,1);
imshow(grayImage);
h = impixelinfo();
axis on;
I2 = imcrop(grayImage,[115, 89, 161-115,142-89]);
subplot(1,2,2);
imshow(I2)
axis on;
  2 Commenti
Aparna Sivakumar
Aparna Sivakumar il 16 Mag 2022
Hi how could you get the follwing values>? imcrop(grayImage,[115, 89, 161-115,142-89]);
Image Analyst
Image Analyst il 16 Mag 2022
I don't know. It looks like the original poster changed/edited his post. It no longer mentions 151 and he removed the image.

Accedi per commentare.

Più risposte (3)

John BG
John BG il 4 Mar 2017
Modificato: John BG il 4 Mar 2017
Hi Hu
A=imread('im1.jpg');imshow(A)
p=ginput(2)
p1max=max(p(:,1));p2max=max(p(:,2));p1min=min(p(:,1));p2min=min(p(:,2));
A(:,[1:p1min],:)=[];
A([1:p2min],:,:)=[];
A(:,[uint64(p1max-p1min+1):end],:)=[];
A([uint64(p2max-p2min+1):end],:,:)=[];
imshow(A)
EXPLANATION
1.
as example let's start with this image
A=imread('im1.jpg');imshow(A)
2. Selecting 2 diagonal points that define the borders you want to remove. I use command ginput but you already have the values
p=ginput(2)
3. Calculating border values from ginput points
p1max=max(p(:,1));p2max=max(p(:,2));p1min=min(p(:,1));p2min=min(p(:,2));
4. Removing on borders, one side of the frame at a time
A(:,[1:p1min],:)=[];
A([1:p2min],:,:)=[];
A(:,[uint64(p1max-p1min+1):end],:)=[];
A([uint64(p2max-p2min+1):end],:,:)=[];
5.
Check
imshow(A)
Hu
if you find these lines useful would you please mark my answer as Accepted Answer?
To any other reader, if you find this answer of any help please click on the thumbs-up vote link,
thanks in advance for time and attention
John BG

Nalini Vishnoi
Nalini Vishnoi il 2 Ott 2014
You can try using the following command
I2 = imcrop(im,[x1 y1 x2-x1 y2-y1]);
imcrop uses the following syntax:
I2 = imcrop(I,RECT);
where RECT is a 4-element vector with the form [XMIN YMIN WIDTH HEIGHT];
  3 Commenti
Geoff Hayes
Geoff Hayes il 2 Ott 2014
hu - please describe what you mean by ...does not work. Perhaps provide an example pair of coordinates with what you expect to be the desired outcome.
hu
hu il 2 Ott 2014
Modificato: hu il 2 Ott 2014
Hi,
If I wish to crop the image (get the square in the middle) and based on the code sugested, It does not work:
I=imread('circuit.tif');
I2 = imcrop(I,[115, 89, 161-151,142-89]);
imshow(I2)
The coordiantes are (115,89,161,142) (Xtop left,Ytop left, Xbottom right, Ybottom right).
Thanks

Accedi per commentare.


Amruta Talreja
Amruta Talreja il 4 Mar 2017
I2 = imcrop(B1,[12659 11677 11281 12661]); imshow(I2); I wrote this code and i am getting a blank screen. plz help.
  4 Commenti
Warid Islam
Warid Islam il 12 Lug 2019
Hi,
Is it possible to crop the image manually without using a rectangle? For example, can I create a boundary manually with a mouse on the Matlab image and display the cropped image separately?
Image Analyst
Image Analyst il 13 Lug 2019
If you use imcrop() without any arguments, you'll be in interactive drawing mode.

Accedi per commentare.

Categorie

Scopri di più su Image Processing and Computer Vision in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by