could anyone help me how to pair the numbers in the desired manner as shown below

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A=1:16
R = reshape(A,4,[])
After executing the above command results in
R =
1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16
Now I want to group the numbers in the desired manner
1 2 3 4 5 6 7 8
12 11 10 9 16 15 14 13
Could anyone please help me on this.

Risposta accettata

Dyuman Joshi
Dyuman Joshi il 2 Nov 2021
This looks a quite a unique manner. Anyways, try this
A=1:16;
R = reshape(A,4,[]);
[R(:,1)' R(:,2)'; flip(R(:,3))' flip(R(:,4))']
ans = 2×8
1 2 3 4 5 6 7 8 12 11 10 9 16 15 14 13
  3 Commenti
Dyuman Joshi
Dyuman Joshi il 3 Nov 2021
Modificato: Dyuman Joshi il 3 Nov 2021
I am not sure what you mean by combining all into a single code, so here's my approach -
for i=[3 4 6 9 12]
z=1:4*i;
y=reshape(z,[],4);
R=[y(:,1)' y(:,2)'; flip(y(:,3))' flip(y(:,4))']
end
R = 2×6
1 2 3 4 5 6 9 8 7 12 11 10
R = 2×8
1 2 3 4 5 6 7 8 12 11 10 9 16 15 14 13
R = 2×12
1 2 3 4 5 6 7 8 9 10 11 12 18 17 16 15 14 13 24 23 22 21 20 19
R = 2×18
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 27 26 25 24 23 22 21 20 19 36 35 34 33 32 31 30 29 28
R = 2×24
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 36 35 34 33 32 31 30 29 28 27 26 25 48 47 46 45 44 43 42 41 40 39 38 37
Here R will be modified in each iteration. You can modify the code according to however you want to proceed.

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Più risposte (1)

Yongjian Feng
Yongjian Feng il 2 Nov 2021
reshape(A, 8, 2)'
  2 Commenti
Yongjian Feng
Yongjian Feng il 2 Nov 2021
Whoops. Didn't pay attention to the order of the second row.
Then we need to use flip most likely.
A=1:16
R = reshape(A,4,[]);
R(:, 3) = flip(R(:, 3));
R(:, 4) = flip(R(:, 4));
ret = reshape(R, 8, 2)'

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