negative eigenvalues in sample covariance matrix

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yasser
yasser il 10 Ott 2014
Risposto: Matt J il 10 Ott 2014
clc; clear;
N=10; taps=2; snr=0; noise_var=0.05;
h1r=randn(1,taps)/sqrt(2); h1i=randn(1,taps)/sqrt(2); h1=complex(h1r,h1i); h1=h1/norm(h1);
h2r=randn(1,taps)/sqrt(2); h2i=randn(1,taps)/sqrt(2); h2=complex(h2r,h2i); h2=h2/norm(h2);
c1=[h1(1);zeros(1,N-1)']; r1=[h1 zeros(1,N-1)]; H1=toeplitz(c1,r1);
c2=[h2(1);zeros(1,N-1)']; r2=[h2 zeros(1,N-1)]; H2=toeplitz(c2,r2);
H=[H1;H2];
order=64; k=log2(order); n=(taps+N-1)*k; x = randi([0 1],n,1); hMod = comm.RectangularQAMModulator(order); hBitToInt = comm.BitToInteger(k);% Convert the bits in x into k-bit symbols. xsym = step(hBitToInt,x); D = modulate(modem.qammod(order),xsym);
X=awgn(H*D,snr,'measured');
% noise1=sqrt(noise_var/2)*(randn(1,size(H1*D,1))+i*randn(1,size(H1*D,2))); % noise2=sqrt(noise_var/2)*(randn(1,size(H2*D,1))+i*randn(1,size(H2*D,2))); % noise=[noise1.';noise2.']; % % X=H*D+noise;
R=X*X'/size(X,2);
[Q ,eig_val]=eig (R);
the problem is that matrix of eig_val has negative values and this can't happen for sample covariance matrix R any help please

Risposte (1)

Matt J
Matt J il 10 Ott 2014
I can't run your code, because you haven't provided all variables needed to run it. However, you can expect small magnitude negative eigenvalues due to floating point errors, if your true covariance matrix ix close to singular.

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