# if the imaginary part of a complex number is zero

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Pooneh Shah Malekpoor il 9 Nov 2021
Risposto: Gargi Patil il 12 Nov 2021
Hello
Here is my code where I want to see if the imaginary part of a number is zero then int=int+1; however, the imaginary part is not considered as zero though using the command by matlab documentation. what should i do?
int=0
F = @(z)((z-20.6667)^2+((-0.5*(z-10))-14.6667)^2-18.1353^2);
opts = optimoptions('fsolve', 'Display', 'off');
z(1) = fsolve(@(z) F(z), 1+1i, opts);
w(1)=-0.5*(z(1)-10);
z(2)=fsolve(@(z) F(z), 30+1i,opts);
w(2)=-0.5*(z(2)-10);
for v=1:2
tt(v)=~any(imag(z(v)));
if (z(v)>10) && (z(v)<=20 || abs(z(v)-20)<1e-6 )&& tt(v)==1
if v==2 && abs(z(1)-z(2))<1e-6
int;
else
int=int+1;
Points(int,:)=[z(v) w(v)];
end
end
end
tt(v) must be 1 for both roots of the equation.
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### Risposte (1)

Gargi Patil il 12 Nov 2021
Hi,
My understanding is that you would like to detect imaginary values equal to zero at the following line:
tt(v)=~any(imag(z(v)));
However, upon closest inspecting the imaginary values of z, they are not exactly zero. For example, the imaginary value of z(1) is 0.000000002392847.
To consider this value as zero, the round function can be used as follows:
nearestDecimalDigit = 4; %set the number of digits as required
tt(v)=~any(round(imag(z(v)), nearestDecimalDigit)); %round to the nearest 4 decimal digits
This sets both the values of tt as 1.
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