Find position of the maximum value and then convert the row zeros and the position of the maximum value should become 1. just like in the image attach

Answer 1

[KSSV]

A = rand(4) ;

[m,n] = size(A) ; 
B = zeros(m,n) ; 
[val,i] = max(A,[],2) ; 

idx = sub2ind(size(A),(1:m)',i) ;
B(idx) = 1 ;

[Adil Sardar]

Thank you..

This output is from simulink I saved it in a file.. Instead of saving it how to apply this method in simulink for running time so that I get the output in binary format.