How do you extract the actual name of your input variable in a function?

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I need to extract the actual name of my input variable for naming a file. Here is my simple script.
function bmp=array2bmp(a)
bmp=uint8(a);
nam=strcat(varname(a),'.bmp');
imwrite(bmp,nam,'bmp');
end
and varname is a function defined as such
function n=varname(var)
n=inputname(1);
end
so if I have an array named 'testbmp' and I type
bmp=array2bmp(testbmp);
My output is a .bmp file named 'a.bmp' not 'testbmp.bmp'. This does not make sense to me. Is there a way I can call the actual name of my actual input variable instead of whatever dummy variable I wrote in the function?

Risposta accettata

Geoff Hayes
Geoff Hayes il 30 Ott 2014
Alex - it does make sense since you are passing a variable named a into your function varname. To get the variable name testbmp, you would have to call inputname(1) from the within the function that "receives" this variable as an input I.e. array2bmp.
  1 Commento
Alex
Alex il 30 Ott 2014
This worked. Thank you for your detailed explanation which helped me understand the reasoning behind the problem.

Accedi per commentare.

Più risposte (1)

Robert Cumming
Robert Cumming il 30 Ott 2014
can you not just do this:
function bmp=array2bmp(a)
bmp=uint8(a);
nam=strcat(inputname(1),'.bmp');
imwrite(bmp,nam,'bmp');
You dont need your sub function varname

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