reason of getting zero answer

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Habib
Habib il 11 Nov 2014
Commentato: Habib il 12 Nov 2014
I write below code for solve diffraction integral by trapz order but in final I have got zero answer for u2. what is problem? please help to find defect.
%gaussian propagation%
clear
clc
r_1=linspace(-1,1,50);
r_2=linspace(-1,1,50);
[r1,r2]=meshgrid(linspace(-1,1,100));
z2=4.2; % is the axial distance from the beam's narrowest point
z1=1;
L=z2-z1;
wvl=500; % is wavelength
k=2*pi./wvl;
w0=sqrt(wvl.*z1./pi); % is the waist size
w1=w0.*sqrt(1+wvl.*z1./pi.*w0.^2); % is the radius at which the field amplitude and intensity drop to 1/e and 1/e2 of...
%...their axial values, respectively,
w2=w0.*sqrt(1+wvl.*z2./pi.*w0.^2);
R1=z1.*(1+(pi.*w0.^2./wvl.*z1).^2); % is the radius of curvature of the beam's wavefronts
R2=z2.*(1+(pi.*w0.^2./wvl.*z2).^2);
u1=w0./w1.*exp((-1./w1.^2+1i.*pi./wvl.*R1).*(r1.^2+r2.^2)-1i.*k.*z1); % mathematical form of Gaussian beam
figure(1)
mesh(r1,r2,real(u1))
K=zeros(1,length(r1));
u1=zeros(1,length(r1));
u2=zeros(1,length(r1));
for nn=1:50
for mm=1:50
r1=linspace(0,1,length(r1));
r2=linspace(0,1,length(r1));
K=exp(-1i.*pi.*(r1(nn).^2+z1.^2+r2(mm).^2+z1.^2-2.*(r1(nn).*r2(mm)+z1.*z2))./(wvl.*L)-1i.*k.*L);
u1=w0./w1.*exp((-1./w1.^2+1i.*pi./wvl.*R1).*(r1(nn).^2+r2(mm).^2)-1i.*k.*z1);
u2(nn,mm)=trapz(K.*u1);
end
end
  2 Commenti
Zoltán Csáti
Zoltán Csáti il 11 Nov 2014
Please format your code so that we can read it easier.
the cyclist
the cyclist il 11 Nov 2014
Did it for him.

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Risposte (1)

the cyclist
the cyclist il 11 Nov 2014
I have not tried to fully understand your code, but the specific reason that u2 is all zeros is that when you calculate
u2(nn,mm)=trapz(K.*u1)
both K and u1 are scalars, and the numerically evaluated integral of a scalar is zero.
  5 Commenti
the cyclist
the cyclist il 12 Nov 2014
The following will run to completion. It seems that it might do what you intend, but I am not certain of that.
clear
clc
r_1=linspace(-1,1,50);
r_2=linspace(-1,1,50);
[r1,r2]=meshgrid(linspace(-1,1,100));
z2=4.2; % is the axial distance from the beam's narrowest point
z1=1;
L=z2-z1;
wvl=500; % is wavelength
k=2*pi./wvl;
w0=sqrt(wvl.*z1./pi); % is the waist size
w1=w0.*sqrt(1+wvl.*z1./pi.*w0.^2); % is the radius at which the field amplitude and intensity drop to 1/e and 1/e2 of...
%...their axial values, respectively,
w2=w0.*sqrt(1+wvl.*z2./pi.*w0.^2);
R1=z1.*(1+(pi.*w0.^2./wvl.*z1).^2); % is the radius of curvature of the beam's wavefronts
R2=z2.*(1+(pi.*w0.^2./wvl.*z2).^2);
u1=w0./w1.*exp((-1./w1.^2+1i.*pi./wvl.*R1).*(r1.^2+r2.^2)-1i.*k.*z1); % mathematical form of Gaussian beam
figure(1)
mesh(r1,r2,real(u1))
K=zeros(1,length(r1));
u1=zeros(1,length(r1));
u2=zeros(1,length(r1));
r1=linspace(0,1,length(r1));
r2=linspace(0,1,length(r1));
for nn=1:50
for mm=1:50
K(nn,mm)=exp(-1i.*pi.*(r1(nn).^2+z1.^2+r2(mm).^2+z1.^2-2.*(r1(nn).*r2(mm)+z1.*z2))./(wvl.*L)-1i.*k.*L);
u1(nn,mm)=w0./w1.*exp((-1./w1.^2+1i.*pi./wvl.*R1).*(r1(nn).^2+r2(mm).^2)-1i.*k.*z1);
end
u2(nn)=trapz(r1,K(nn,:).*u1(nn,:));
end
Habib
Habib il 12 Nov 2014
thank you for your reply and your kindness
your codes worked, but if we can plot u2, it is understandable that the Trapz worked correctly or not!!!
if it is not bothered you,I have another question!!!
my question is about plot u2, how we can plot u2 by mesh, surf or another plot commands?
(I want plot it as a three-dimensional surface)

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