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how to form loop to jump from one element of matrix to other element.

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Hi friends,
N_temp_failure= [ 938 945 955 2002 2003 4565 4566 4567 ];
Nx=937;
while Nx<=4567 ( i mean last element of N_temp_failure ).
Nx=Nx+0.001;
if Nx ==938
Nx= 945-1; (i mean it should jump to second element of N_temp_failure subtracted by 1 )
else
Nx=Nx;
end
end
it should repeat after Nx reaches every element of N_temp_failure, until it reaches the last element. N_temp_failure will always be in ascending order.
Please help me,
Advance Thanks Jagadesh Rao Thalur
  2 Commenti
Thorsten
Thorsten il 21 Nov 2014
Modificato: Thorsten il 21 Nov 2014
Add 0.001 to each element of N_temp_failure, unless the i'th element is 938, in this case you have to subtract 1 from the ith and the ith+1 element; is that what you want?
Jagadesh Rao
Jagadesh Rao il 22 Nov 2014
yes, you got it. you have a solution for it? please tell me.

Risposte (1)

Manoj
Manoj il 21 Nov 2014
Does this do what you want ?
N_temp_failure= [ 938 945 955 2002 2003 4565 4566 4567 ];
for ii=1:size(N_temp_failure,2)-1
Nx=N_temp_failure(ii)-1;
while Nx <= N_temp_failure(end);
Nx=Nx+0.001;
if Nx==N_temp_failure(ii)
Nx=N_temp_failure(ii+1)-1;
else
Nx=Nx;
end
end
end
  2 Commenti
Jagadesh Rao
Jagadesh Rao il 21 Nov 2014
actually your answer is partially correct, you should have put for loop inside while loop, you did the opposite. thanks
Jagadesh Rao
Jagadesh Rao il 22 Nov 2014
I tried this , this didn't work, it doesn't give the jump i asked for.
please try some other way.

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