Inconsistent row/column dimensions.

l=633*(10)^(-9);
k0=(2*pi)/l;
nc=1.33;
na=1.43265;
nf=1.59;
nm=0.064+1i*4;
ns=1.49;
a=54:0.01:70
df=1:1:300;
nf=1.59;
k0=(2*pi/633);
Nm=nf*sind(a);
Snc=zeros(length(a),length(df));
Sna=zeros(length(a),length(df));
Sda=zeros(length(a),length(df));
p=1;
ds=((1-p)./(k0.*sqrt(Nm.^2-ns.^2)))+(p./((Nm./nf).^2+(Nm./ns).^2-1).*(k0.*sqrt(Nm.^2-ns.^2)));
dc=((1-p)./(k0.*sqrt(Nm.^2-nc.^2)))+(p./((Nm./nf).^2+(Nm./nc).^2-1).*(k0.*sqrt(Nm.^2-nc.^2)));
da=((1-p)./(k0.*sqrt(Nm.^2-na.^2)))+(p./((Nm./nf).^2+(Nm./na).^2-1).*(k0.*sqrt(Nm.^2-na.^2)));
Snc= ((nc/Nm).*((nf.^2-Nm.^2)./(nf.^2-nc.^2)).*(dc./(ds+df+dc)).*(2.*(Nm.^2./nc.^2)-1));
Sna= ((na./Nm).*((nf.^2-Nm.^2)./(nf.^2-na.^2)).*(da./(ds+df+da)).*(2.*(Nm.^2./na.^2)-1));
Sda= (((nf.^2-Nm.^2)./(Nm.*(ds+df+dc))).*((na.^2-nc.^2)./(nf.^2-nc.^2)).*((((Nm./nc).^2)+((Nm./na).^2)-1)./( ((Nm./nc).^2)+((Nm./nf).^2)-1))).^p;
plot(df,Snc)

 Risposta accettata

l=633*(10)^(-9);
k0=(2*pi)/l;
nc=1.33;
na=1.43265;
nf=1.59;
nm=0.064+1i*4;
ns=1.49;
a=54:0.01:70 ;
df=linspace(1,300,length(a));
nf=1.59;
k0=(2*pi/633);
Nm=nf*sind(a);
p=1;
ds=((1-p)./(k0.*sqrt(Nm.^2-ns.^2)))+(p./((Nm./nf).^2+(Nm./ns).^2-1).*(k0.*sqrt(Nm.^2-ns.^2)));
dc=((1-p)./(k0.*sqrt(Nm.^2-nc.^2)))+(p./((Nm./nf).^2+(Nm./nc).^2-1).*(k0.*sqrt(Nm.^2-nc.^2)));
da=((1-p)./(k0.*sqrt(Nm.^2-na.^2)))+(p./((Nm./nf).^2+(Nm./na).^2-1).*(k0.*sqrt(Nm.^2-na.^2)));
Snc= ((nc./Nm).*((nf.^2-Nm.^2)./(nf.^2-nc.^2)).*(dc./(ds+df+dc)).*(2.*(Nm.^2./nc.^2)-1));
Sna= ((na./Nm).*((nf.^2-Nm.^2)./(nf.^2-na.^2)).*(da./(ds+df+da)).*(2.*(Nm.^2./na.^2)-1));
Sda= (((nf.^2-Nm.^2)./(Nm.*(ds+df+dc))).*((na.^2-nc.^2)./(nf.^2-nc.^2)).*((((Nm./nc).^2)+((Nm./na).^2)-1)./( ((Nm./nc).^2)+((Nm./nf).^2)-1))).^p;
plot(df,Snc)
Warning: Imaginary parts of complex X and/or Y arguments ignored.

8 Commenti

how we use zeros in this program
KSSV
KSSV il 10 Feb 2022
What zeros?
use of zeros of the df
KSSV
KSSV il 10 Feb 2022
Did you raise any question regarding use of zeros of df? What was your question and what you are expecting?
if you have idea of using zeros so pl help because I have use zeros in initial program
KSSV
KSSV il 10 Feb 2022
I know zero is represented by 0. How and why you want to use here?
for exaple this type of program example program for use of zeros for initialization
function kk1
clc;clear;close all;
l=633;
c = 1;
k0=2*pi/l;
ea=1.39;
da=1:300;
theta=1:70;
y=zeros(length(theta),length(da));
np=1.5;
x=(2*pi/l)*np*sind(theta);
function y=f(theta,da)
for i=1:length(theta)
iter = 0;
for j=1:length(da)
iter
ka=k0*sqrt(ea-x.^2);
f=(1-exp(2*1i.*da(j).*ka(i)))/(1+exp(2*1i.*da(j).*ka(i)));
%pfms=2*atan(1i*a.*b);
y(i,j)=2*atan(1i*c.*f);
% disp(y);
iter = iter + 1;
end
end
end
plot(da,y )
end
KSSV
KSSV il 10 Feb 2022
Jeez you want to use initilization?
If you are using a loop and filling values into it, you have to initalize the array using zeros.
If you are not using loop and getting the LHS by vectorization, no loop is needed.

Accedi per commentare.

Più risposte (1)

It seems there is a problem in Snc solution. ds and dc are vectors of 1601 elements whereas df has 300 elements.
Snc= ((nc/Nm).*((nf.^2-Nm.^2)./(nf.^2-nc.^2)).*(dc./(ds+df+dc)).*(2.*(Nm.^2./nc.^2)-1));
The same in Sna line:
Sna= ((na./Nm).*((nf.^2-Nm.^2)./(nf.^2-na.^2)).*(da./(ds+df+da)).*(2.*(Nm.^2./na.^2)-1));
I don't know the aim of df but try initializing the same length as ds.

Categorie

Scopri di più su Programming in Centro assistenza e File Exchange

Prodotti

Release

R2021b

Tag

Richiesto:

il 10 Feb 2022

Commentato:

il 10 Feb 2022

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by