Determining the length of a 3D spiral
6 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Hassan Moheb Abdulrahman Yousef
il 20 Feb 2022
Modificato: Image Analyst
il 20 Feb 2022
I made a program to create a spiral but I don't know how to determine the length of it.
clear all
clc
dh=0.5; %step depth
a=45; %angle of inclination of cone
h=30; %depth of the cone
R1=50; %largest radius of the cone
D=R1*tand(a);
N=h/dh; %Number of loops or contour
m=1;
for n=0:1:360*N %dividing a loop into 360 angles
Z(m)=0-((dh/360)*n);
R=R1-(((dh/360)*n)/tand(a)); %radius at any depth
X(m)=R*cosd(n);
Y(m)=R*sind(n);
m=m+1;
end
plot3(Y,X,Z,'y') %3d visualization of helix
0 Commenti
Risposta accettata
Image Analyst
il 20 Feb 2022
Did you try the Euclidean distance? Something like
deltaX = diff(X);
deltaY = diff(Y);
deltaZ = diff(Z);
distance = sum(sqrt(deltaX.^2 + deltaY.^2 + deltaZ.^2))
4 Commenti
Image Analyst
il 20 Feb 2022
Did it solve it? If so, could you click the "Accept this answer" link? 🙂
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Elementary Math in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!