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How to give ranking from highest to lowest

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Hello, I have number like
Data=[5 6 9 1 5 2]
I want to rank them as: [3 2 1 6 4 5] Can any please help me How can I do this. Thanks in advance.
  1 Commento
amrith sg
amrith sg il 31 Mar 2022
i got a average accuracy 79% at rank 1
from rank 2 to rank 10 , i need to find different average accuracy that should be greater than 79%
please give me the code regarding this problem

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Risposta accettata

Roger Stafford
Roger Stafford il 6 Dic 2014
This should give you the rank you are asking for, Mekala:
[~,p] = sort(Data,'descend');
r = 1:length(Data);
r(p) = r;
'r' will be the ranking.
  1 Commento
Image Analyst
Image Analyst il 27 Gen 2024
Data=[5 6 9 1 5 2]
Data = 1×6
5 6 9 1 5 2
% I want to rank them as: [3 2 1 6 4 5]
[~,p] = sort(Data,'descend');
r = 1:length(Data);
r(p) = r
r = 1×6
3 2 1 6 4 5

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Più risposte (4)

Azzi Abdelmalek
Azzi Abdelmalek il 6 Dic 2014
Modificato: Azzi Abdelmalek il 6 Dic 2014
Data=[5 6 9 1 5 2]
[sd,r]=sort(Data,'descend')
sd % sorted data
r % the corresponding indices
  5 Commenti
Azzi Abdelmalek
Azzi Abdelmalek il 6 Dic 2014
Ok Roger, I understand now.
Azzi Abdelmalek
Azzi Abdelmalek il 6 Dic 2014
We can get the result by sorting the indices resulting from the first sort
Data=[5 6 9 1 5 2]
[~,ii]=sort(Data,'Descend')
[~,r]=sort(ii)

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Sandeep Sai Kiran
Sandeep Sai Kiran il 9 Feb 2021
Modificato: Image Analyst il 27 Gen 2024
Data =[4 8 9 4 7 4]
Data = 1×6
4 8 9 4 7 4
Kal = sort(Data , 'Descend')
Kal = 1×6
9 8 7 4 4 4
Kapil =sort(Kal)
Kapil = 1×6
4 4 4 7 8 9

Zalán Kocsis
Zalán Kocsis il 2 Giu 2021
Modificato: Image Analyst il 27 Gen 2024
Here's one that assigns the same rank to same values (ties):
Data=[5 6 9 1 5 2];
[C,~,ic] = unique(Data,'sorted'); % ic are ranks from lowest to highest ; C are unique values
r=(1+max(ic)-ic); % r: rank (highest receives 1; lowest receives length(C); tied values receive same rank)
[Data;r']
ans = 2×6
5 6 9 1 5 2 3 2 1 5 3 4

ASWIN
ASWIN il 27 Gen 2024
Modificato: Image Analyst il 27 Gen 2024
A=ones(4);
m=length(A);
r=rank(A)
r = 1
  2 Commenti
Dyuman Joshi
Dyuman Joshi il 27 Gen 2024
Modificato: Dyuman Joshi il 27 Gen 2024
That rank() is different from what OP is asking about.
Image Analyst
Image Analyst il 27 Gen 2024
By "ranking" he really meant sorting. Your solution does not give the answer of [3 2 1 6 4 5] that he asked for.

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