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How can I apply a logical mask to an image variable?

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Hello,
I am trying to apply a logical mask to an image variable, however I couldnt manage to do it so far.
I have tried
maskedRgbImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
maskedRgbImage = rgbImage.*mask
Also, I've tried to apply mask to the rgbImage.CData directly. All of them are giving me errors. What else I can try?
Thank you so much
  2 Commenti
Walter Roberson
Walter Roberson il 24 Feb 2022
Your rgbImage is a handle to a deleted image() object -- not an array of data.
dila suay
dila suay il 24 Feb 2022
Hi Walter, thank you for your quick reply. I uploaded a .fig version. I hope it is useful

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Walter Roberson
Walter Roberson il 24 Feb 2022
rgb = rgbImage.CData;
maskedImage = rgb .* cast(repmat(c, [1 1 size(rgb,3)]),'like',rgb);
This cannot be an image() object unless you want to do something like
maskedRgbImage = copyobj(rgbImage, gca);
rgb = rgbImage.CData;
maskedImage.CData = rgb .* cast(repmat(c, [1 1 size(rgb,3)]),'like',rgb);
... but that would be directly on top of the old image.
  2 Commenti
dila suay
dila suay il 24 Feb 2022
Thank you so much for your quick replies Walter. It says
Unrecognized function or variable 'c'.
What is c?
Walter Roberson
Walter Roberson il 24 Feb 2022
rgb = rgbImage.CData;
maskedImage = rgb .* cast(repmat(mask, [1 1 size(rgb,3)]),'like',rgb);
or
maskedRgbImage = copyobj(rgbImage, gca);
rgb = rgbImage.CData;
maskedImage.CData = rgb .* cast(repmat(mask, [1 1 size(rgb,3)]),'like',rgb);

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Più risposte (1)

Image Analyst
Image Analyst il 24 Feb 2022
You don't need to do both of these:
maskedRgbImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
maskedRgbImage = rgbImage.*mask
All you need is the first one. Don't do the second one. It's not right and would need "fixing".
  1 Commento
Kaitlin Wang
Kaitlin Wang il 24 Feb 2022
sir you are my hero. i have been looking at your answers for weeks and learning so much. thank you

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