Azzera filtri
Azzera filtri

Index exceeds matrix dimensions error

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hi i was running this simple code,but i got this error,any idea how to fix it?
L = 140; % Length of signal
NFFT = 2^nextpow2(L); % Next power of 2 from length of y
YY = fft(rawdata,NFFT)/L;
((((((((((Index exceeds matrix dimensions.))))))))
Error in Untitled2 (line 11)
YY = fft(rawdata,NFFT)/L;
  4 Commenti
Star Strider
Star Strider il 10 Dic 2014
Next step:
In the Command Window, type
which fft -all
after the error.
I get 6 answers, all in: C:\Program Files\MATLAB\.
mohamad mohamad
mohamad mohamad il 10 Dic 2014
Modificato: Star Strider il 10 Dic 2014
fft is a variable.
built-in (C:\MATLAB\R2012a\toolbox\matlab\datafun\@logical\fft) % Shadowed logical method
built-in (C:\MATLAB\R2012a\toolbox\matlab\datafun\@single\fft) % Shadowed single method
built-in (C:\MATLAB\R2012a\toolbox\matlab\datafun\@double\fft) % Shadowed double method
C:\MATLAB\R2012a\toolbox\matlab\datafun\@uint8\fft.m % Shadowed uint8 method
C:\MATLAB\R2012a\toolbox\matlab\datafun\@uint16\fft.m % Shadowed uint16 method
C:\MATLAB\R2012a\toolbox\comm\comm\@gf\fft.m % Shadowed gf method
C:\MATLAB\R2012a\toolbox\distcomp\parallel\@codistributed\fft.m % Shadowed codistributed method
C:\MATLAB\R2012a\toolbox\dsp\filterdesign\@qfft\fft.m % Shadowed qfft method
C:\MATLAB\R2012a\toolbox\ident\ident\@iddata\fft.m % Shadowed iddata method

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Image Analyst
Image Analyst il 10 Dic 2014
How can you take 256 samples from an array with 140 samples? Maybe you need to pad it with zeros or something
newArray = [oldArray, zeros(1, NFFT - length(oldArray))];
  6 Commenti
mohamad mohamad
mohamad mohamad il 10 Dic 2014
my vector was a column vector and could not be concatenated with row vector zeros(1, NFFT - length(rawdata)).so i changed it to zeros(NFFT - (length(rawdata)), 1)]; and it works properly thanks indeed for your fast replays
Image Analyst
Image Analyst il 10 Dic 2014
OK, glad it works, though I don't know why since the help for fft() said that it would do that padding for you.

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