How do you divide 120 by x when x is (3,6] starting with x=0

I am trying to do a while statement that divdes 120 by the numbers between (3,6] and only gives nonzero() answers, but so far my code only gives me the last value "20". Is there a way to fix the code so I get all three values, 30, 24, and 20?

x=0;
while (x>2) & (x<=5)
    x=x+1;
    Q2(x) = 120/x;
end

disp('Q2 =')

Q2 =

disp(nonzeros(Q2))

Unrecognized function or variable 'Q2'.

Answer 1

[Walter Roberson]

x=0;
while (x>2) & (x<=5)

Your x starts out at 0 which immediately fails the x>2 test.

Consider

x=0;
while x<=6
  if (x>3) & (x<=6)

Now imagine that you were keeping a counter of how many values you have found, and you used the counter to index the output variable...

Answer 2

[David Hill]

Q2=120./(4:6)