How to read part of folder
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I have my data saved into folders based on time of creation. the structure is like this:
folder: 05_dec._2014_08-15-03.331_GMT+00-00
files: OneName_05_dec._2014_08-15-03.331_GMT+00-00.txt
AnotherName_05_dec._2014_08-15-03.331_GMT+00-00.txt
JetAnotherName_05_dec._2014_08-15-03.331_GMT+00-00.txt
How can i do so that every time i add a folder, i'll need to only give the folder name and it will read file names based on some schema.
for example
First = csvread('OneName_whatever_folder_name.txt')
Second = csvread('AnotherName_whatever_folder_name.txt');
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Risposte (2)
Orion
il 12 Dic 2014
you can use fullfile
Folder = 'C:\users\....\05_dec._2014_08-15-03.331_GMT+00-00'; % put your own folder path
File = 'OneName_whatever_folder_name.txt';
csvread(fullfile(Folder,File))
Guillaume
il 12 Dic 2014
Modificato: Guillaume
il 12 Dic 2014
How about:
foldername = 'whatever'; %adjust to folder name, your input.
basepath = 'C:\somewhere\ondisk'; %adjust as required. A constant.
filesinfolder = dir(fullfile(basepath, foldername, sprintf('*_%s.txt', foldername)));
filecontent = cell(numel(filesinfolder), 1);
for filecount = 1 : numel(filesinfolder)
filecontent{filecount} = csvread(fullfile(basepath, foldername, filesinfolder(filecount).name));
end
2 Commenti
Guillaume
il 12 Dic 2014
Modificato: Guillaume
il 12 Dic 2014
I've not understood your pattern then, I thought the file names were just the folder name preceded by something and an underline _ and followed by .txt. If that's not the case, then yes, filesinfolder will be empty.
What does the following outputs?
d = dir(fullfile(basepath, foldername));
fullfile(foldername, {d.name}')
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