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Change string of text into multiple lines

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I have a string of text that needs to be formatted and saved as a txt file. The string is in this format:
,1,1880802442166,1,751702411341,1,751702411358,1,751702411365,1,751702411372,1,751702411389,1,751702459060,1,751702459077,1,751702459084,3,751702459091,1,751702459107,1,751702459114,2,751702459121,1,751702459145...
It needs to be output in this format:
,1,1880802442166
,1,751702411341
,1,751702411358
,1,751702411365
,1,751702411372
,1,751702411389
,1,751702459060
,1,751702459077
,1,751702459084
,3,751702459091
,1,751702459107
,1,751702459114
,2,751702459121
,1,751702459145...
It's for an inventory list that was recorded in the wrong format.
Thanks in advance,
Nick

Risposta accettata

Azzi Abdelmalek
Azzi Abdelmalek il 20 Dic 2014
s=',1,1880802442166,1,751702411341,1,751702411358,1,751702411365,1,751702411372,1,751702411389,1,751702459060,1,751702459077,1,751702459084,3,751702459091,1,751702459107,1,751702459114,2,751702459121,1,751702459145'
a=regexp(s,',','split')
a(1)=[]
b=reshape(a,2,[])'
c=cellfun(@(x,y) [',' x ',' y], b(:,1),b(:,2),'un',0)
fid=fopen('file.txt','w')
for k=1:numel(c)
fprintf(fid,'%s \r\n',c{k,:})
end
fclose(fid)
  1 Commento
Nicholas
Nicholas il 20 Dic 2014
I needed a blank line between each in value in the list, but I just added an extra
\r\n
in
fprintf(fid,'%s \r\n',c{k,:})
Thanks

Accedi per commentare.

Più risposte (1)

Andrei Bobrov
Andrei Bobrov il 20 Dic 2014
Modificato: Andrei Bobrov il 20 Dic 2014
s = ',1,1880802442166,1,751702411341,1,751702411358,1,751702411365,1,751702411372,1,751702411389,1,751702459060,1,751702459077,1,751702459084,3,751702459091,1,751702459107,1,751702459114,2,751702459121,1,751702459145';
out = mat2cell(s,1,diff([regexp(s,',\d,'),numel(s)+1]))

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