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problem with the rank of controllability of a system

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I have this system given below
A=[-3.87695312500000e-06,-0.000377259521484375,-1.54541015625000e-06,-2.47435565751281e-05,0;
-0.000383031005859375,-0.0438680297851563,-0.000171501464843750,-0.00287715774129662,0;
-1.68273925781250e-06,-0.000184232788085938,-3.42102050781250e-06,-1.20840625134364e-05,0;
-0.0288955468750000,-3.30957816406250,-0.0129358593750000,-0.452124041742296,0.00180860517844498;
0,0,0,119.959269051020,-1.23669349537147]
B=[-0.000202364643587302;-0.0235307725101629;-9.88292445427022e-05;-1.42966622638009;0];
C=eye(5);
D=zeros(5,1);
the rank of the controlablity matrix gives me the following matrix
co=ctrb(A,B);
>> co=[-0.000202364643587302,4.42531724232830e-05,-1.98625050253011e-05,1.70702903536278e-05,-2.16416261767110e-05;-0.0235307725101629,0.00514571834133656,-0.00230959374267344,0.00198491754360988,-0.00251646821219010;-9.88292445427022e-05,2.16119945020915e-05,-9.70028879196148e-06,8.33665147162803e-06,-1.05691645905590e-05;-1.42966622638009,0.724270529374834,-0.654670725177827,0.844370048676126,-1.19908774023253;0,-171.501715503486,298.978019307210,-448.277993397705,655.672492400879]
Rank (co) returns 4 where as it seems it should be 5?
  1 Commento
Kamran
Kamran il 25 Mar 2022
For the given system, I can develop an lqr with following paratmers
R=diag([1e1,1e3,1e1,1e2,10]);
Q=1e2;
K=lqr(A,B,R,Q);
So I dont understand the rank of controlablity martix be 4 and not 5.

Accedi per commentare.

Risposte (1)

Sachin Lodhi
Sachin Lodhi il 19 Dic 2023
Modificato: Sachin Lodhi il 19 Dic 2023
Hi Kamran,
The controllability matrix 'co' has a rank of 4 instead of 5 because the first row is just the third row multiplied by 2. It means that these two rows are linearly dependent.
In terms of rank, which measures the dimension of the row or column space (the maximum number of linearly independent rows or columns), having two linearly dependent rows reduces the rank of the matrix by at least one.
So, in matrix ‘co’ of [5 x 5] dimension, if two rows are the same, the number of linearly independent rows would be '5-1 = 4', and thus the rank of the matrix would be 4.
I hope this helps.
Best Regards,
Sachin

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