How to store consequtive numbers and vector jumps in different matrices?

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OK guys, lets say i have a matrix A=[1,2,3,6,7,8,11,12,13,14,15,17,18,19,30,31,32] , i want to locate the consequtive numbers and store them in matrices ,and also the the values that are not consequtive and store them in different matrices.So the output should be like:
A1=[1 2 3] B1=[3 6]
A2=[6 7 8 ] B2=[8 11]
A3 = [11 12 13 14 15 ] B3 = [15 17]
A4=[17 18 19 ] B4=[19 30]
A5=[ 30 31 32]
Any idea how can i solve this?

Risposta accettata

Riccardo Scorretti
Riccardo Scorretti il 25 Mar 2022
Modificato: Riccardo Scorretti il 25 Mar 2022
Hi. You can try this:
A = [1,2,3,6,7,8,11,12,13,14,15,17,18,19,30,31,32];
C = {} ; NC = {}; % Consecutive / Non Consecutive vectors
ind = find(diff(A)~=1);
for n = 1 : numel(ind), NC{n} = A(ind(n):ind(n)+1) ; end
ind = [1 ind+1 numel(A)+1];
for n = 1 : numel(ind)-1, C{n} = A(ind(n):ind(n+1)-1) ; end
C
C = 1×5 cell array
{[1 2 3]} {[6 7 8]} {[11 12 13 14 15]} {[17 18 19]} {[30 31 32]}
NC
NC = 1×4 cell array
{[3 6]} {[8 11]} {[15 17]} {[19 30]}
  4 Commenti
Riccardo Scorretti
Riccardo Scorretti il 25 Mar 2022
You mean, like that?
A = [1,2,3,6,7,8,11,12,13,14,15,17,18,19,30,31,32];
C = {} ; NC = {}; % Consecutive / Non Consecutive vectors
figure
ind = find(diff(A)~=1);
for n = 1 : numel(ind)
NC{n} = A(ind(n):ind(n)+1);
plot(ind(n):ind(n)+1, NC{n}, 'r') ; hold on;
end
ind = [1 ind+1 numel(A)+1];
for n = 1 : numel(ind)-1
C{n} = A(ind(n):ind(n+1)-1);
plot(ind(n):ind(n+1)-1, C{n}, 'b');
end
C
C = 1×5 cell array
{[1 2 3]} {[6 7 8]} {[11 12 13 14 15]} {[17 18 19]} {[30 31 32]}
NC
NC = 1×4 cell array
{[3 6]} {[8 11]} {[15 17]} {[19 30]}
PANAGIOTIS GEORGIOS ILIOPOUOS
Modificato: PANAGIOTIS GEORGIOS ILIOPOUOS il 25 Mar 2022
Yep nice thanks for answering .
What if i wanted to apply the same code in a datetime matrix?
For example
A = ['29-May-2017 00:02:00' '29-May-2017 00:03:00' '29-May-2017 00:04:00' '29-May-2017 00:08:00'...
'29-May-2017 00:09:00' '29-May-2017 00:010:00' '29-May-2017 00:11:00' '29-May-2017 00:14:00']
so as to find when the time values are non consequtive and also plot them like before.
i thinks its kinda trickier,but any comments would be helpfull.

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Più risposte (1)

David Hill
David Hill il 25 Mar 2022
A=[1,2,3,6,7,8,11,12,13,14,15,17,18,19,30,31,32];
a=diff(A);
n=num2str(a==1);nn=num2str(a~=1);
n=n(n~=' ');nn=nn(nn~=' ');
[s,e]=regexp(n,'[1]+');
[ss,ee]=regexp(nn,'[1]+');
for k=1:length(s)
AA{k}=A(s(k):e(k)+1);
end
for k=1:length(ss)
BB{k}=A(ss(k):ee(k)+1);
end
  2 Commenti
PANAGIOTIS GEORGIOS ILIOPOUOS
Do you know what else i need do add in this code, so as to store the order that each value has in the Matrix A ?
Because i also want to plot the consequtive/non consequtive values in the same figure but with different color,but in the right order.

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