solving PDE with boundary conditions involving derivative

2 visualizzazioni (ultimi 30 giorni)
Hi!
I'm trying to solve a PDE problem with boundary conditions: C(0,t)=Cf & dC(L,t)dz=0
My final goal is to find the C(z,t) and L.
Here is my full code for now:
Da=findDa(d_p,u,epsilon,Rho,eta);%function
constant=findConstant(epsilon, q_max, k_eq);
% z=findz(u, Da,Cf);
z = linspace(0,0.1,50);
t = linspace(0,1,50);
m = 0;
eqn = @(z,t,C,dCdz) setPDE(z,t,C,dCdz,Da,constant,u);
sol = pdepe(m,eqn,@findIC,@setBC,z,t);
C = sol(:,:,1);
function constantVal=findConstant(epsilon, q_max, k_eq)
constantVal=(1+(1-epsilon)/epsilon*q_max*k_eq);
end
function Daval=findDa(d_p,u,epsilon,Rho,eta)
Re=u*d_p*Rho/eta;
Daval=d_p*u*epsilon/(0.339+0.033*Re^0.48);
end
function [g,f,s]=setPDE(z,t,C,dCdz,Da,constant,u)
g=1;
f=Da/constant*dCdz;
s=-u/constant*dCdz;
end
function C0=findIC(z)
C0=0;
end
function [pl,ql,pr,qr]=setBC(zl,Cl,zr,Cr,t)
...
end

Risposta accettata

Torsten
Torsten il 26 Mar 2022
Cf = ...;
bcfcn = @(zl,Cl,zr,Cr,t)setBC(zl,Cl,zr,Cr,t,Cf);
sol = pdepe(m,eqn,@findIC,bcfcn,z,t);
function [pl,ql,pr,qr]=setBC(zl,Cl,zr,Cr,t,Cf)
pl = Cl - Cf;
ql = 0.0;
pr = 0.0;
qr = 1.0;
end
  3 Commenti
Torsten
Torsten il 26 Mar 2022
Check the values of your inputs Da, constant, u and Cf
.
YeEn Kim
YeEn Kim il 26 Mar 2022
I cleared it and it worked!!! Thank you so much!
Though, it still doesn't give me anything in the figure, but I guess I will slowly figure that out...
Thank you for your help XD

Accedi per commentare.

Più risposte (0)

Prodotti


Release

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by