Cycle of operations on vector sections
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Lev Mihailov
il 4 Apr 2022
Commentato: Lev Mihailov
il 4 Apr 2022
I'm trying to make a cycle that would process a section of the vector and return this section to me changed
x=rand(1,2302)
y=rand(1,2302)
step=100;
for i=1:size(x,2)
i1=y(i:i+step);
i2=x(i:i+step);
a(i)=myfun(i1,i2);
end
%% for example my function
function [m,s] = myfun(x,y)
n = length(x);
m = x-0.26;
s= y-0.77
end
thank you in advance
2 Commenti
Risposta accettata
Davide Masiello
il 4 Apr 2022
The problem is myfun spits out two vectors of size 1 x step+1.
You could assign this vectors to the rows of a new matrix (see a and b in the example below) .
x = rand(1,2302);
y = rand(1,2302);
step = 100;
for i = 1:size(x,2)-step
i1 = y(i:i+step);
i2 = x(i:i+step);
[a(i,:),b(i,:)] = myfun(i1,i2);
end
function [m,s] = myfun(x,y)
n = length(x); % <--- not needed
m = x-0.26;
s= y-0.77;
end
3 Commenti
Davide Masiello
il 4 Apr 2022
In that case you can replace
[a(i,:),b(i,:)]
with
[a(:,i),b(:,i)]
so each output of myfun is stored as a column in the matrices a and b.
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Loops and Conditional Statements in Help Center e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!