Adjacent Repeat of Numbers in an Array
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This is the current function
function adjacentRepeat = HasAdjacentRepeat(inArray)
for inArray=diff(inArray)
adjacentRepeat=1;
end
It works to satisfy the following requirements:
- Check for the use of a loop.
- Assessment result: correctCheck adjacentRepeat = 1 for inArray = [2 1 3 3 4 2 5].
- Assessment result: correctCheck adjacentRepeat = 1 for inArray = [4 5 7 6 3 8 9 7 2 8 9 7 3 3 3 7 1].
- Assessment result: correctCheck for correct adjacentRepeat for an array of randomized size and values.
But not for this requirement:
- Assessment result: incorrectCheck adjacentRepeat = 0 for inArray = [1 2 1 2 1].
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Risposta accettata
Image Analyst
il 12 Apr 2022
You never set adjacentRepeat to 0, EVER. So of course it doesn't work.
Did you try just going through your difference array checking if any are 0? If they are, then the adjacent values are the same and you can set the variable and exit.
function adjacentRepeat = HasAdjacentRepeat(inArray)
adjacentRepeat = 0;
d = diff(inArray);
for k = 1 : length(d)
if d(k) == 0
adjacentRepeat = 1;
return;
end
end
end
2 Commenti
Jacob
il 19 Apr 2023
I realized the problem I was having is I didnt understand what was or how to use diff. Thank you, this worked perfectly!
Più risposte (1)
Image Analyst
il 12 Apr 2022
Why do you have a for loop? Why not simply do this:
adjacentRepeat = HasAdjacentRepeat([2 1 3 3 4 2 5])
adjacentRepeat = HasAdjacentRepeat([4 5 7 6 3 8 9 7 2 8 9 7 3 3 3 7 1])
adjacentRepeat = HasAdjacentRepeat([1 2 1 2 1])
function adjacentRepeat = HasAdjacentRepeat(inArray)
adjacentRepeat = any(diff(inArray) == 0);
end
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