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Basic Shift Cipher Decryption Algorithm HELP!

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Hello guys, I'm using matlab to make a function that basically decrypts a shift cipher by taking in the ciphertext string and key integer as parameters and returning the plaintext.
here is the code..
function [ plainText ] = ccdt( c, k )
s = double(c);
for i = 1:numel(s)
s(i) = s(i)-k;
plainText = char(s);
This works fine when the letters don't necessarily need to loop back around to the beginning of the alphabet. For example, if I decrypt the letter 'b' with key = 3, it should give me back 'y', but it's just returning whatever ascii code for 'b' minus 3 which isn't 'y'.
How can I fix this problem? also, how can i modify the code so that lower/ upper case letters don't really matter?
Thanks for your time!

Risposta accettata

Mohammad Abouali
Mohammad Abouali il 11 Gen 2015
Modificato: Mohammad Abouali il 11 Gen 2015
Use mode or reminder to loop over certain range of numbers. Something like this:
% A --> 65
% Z --> 90
% a --> 97
% z --> 122
inputChar=char( [ (65:90)'; (97:122)'] );
for i=1:numel(inputChar)
if ( numericChar>=65 && numericChar<=90 )
elseif ( numericChar>=97 && numericChar<=122 )
error('just alphabetic chars are accepted')
You can use both negative shift or positive shift, depending on the direction.
  2 Commenti
Jason il 11 Gen 2015
ah thanks for this. so basically, the only way to guarantee that the function shifts in between the ascii codes for the lower/upper case alphabet characters is to use multiple if/else to check that they are in between 65:90 and 97:122?
Mohammad Abouali
Mohammad Abouali il 11 Gen 2015
Not really. There are other approaches too.
You can prebuilt a lookup table. Or you can change everything to upper case and cycle there and then restore the caps (lower or upper).
I am sure we can find couple of other methods to get the same output.

Accedi per commentare.

Più risposte (2)

Aman Gupta
Aman Gupta il 27 Giu 2019
function coded = caesar(x,n)
a = double(x);
a = a+n;
for i = 1:length(a)
while (a(i)>126 || a(i)<32)
if a(i)>126
a(i) = 31 + (a(i) - 126);
elseif a(i)<32
a(i) = 127 - (32 - a(i));
coded = char(a);

Rahul Gulia
Rahul Gulia il 22 Lug 2019
function coded = caesar(str,n)
num1 = double(str); %Converting string to double to make the defined shifts
for i = 1 : length(num1)
if num1(i) + n > 126 % If ASCII value goes beyond 126
m = num1(i)-126+n;
p = 31+m;
num1(i) = p;
elseif num1(i)+n < 32 % If ASCII value goes below 32
m = 32 - num1(i) + n;
p = 126 - m;
num1(i) = p;
else m = num1(i) + n; % In a normal condition
num1(i) = m;
code(i) = num1(i);
coded = char(code);
% I have written this code. Can anyone please expain as what is wrong in here? I know i have made a mistake. But i am not able to figure it out.
% Thanks in advance.


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