Creating an array for a set number iterations

I currently have the code that I have made for calculating a value Ct. But for this code I am trying to modify it such that I can calulate the array of values of Ct, for the values of i being from 1 to 30. I have tried a for loop but just cant get it to output the right values. F must be added to the last value of Ct. If i = 3 then there should be three elements in the array Ct which are [4000 4000 104000]

F = 100000;  
i = 1;
Ct= F*0.04.*ones(i,1);
Ct(i) =Ct(i)+F;
T=length(Ct);
t=(1:1:T)';

Answer 1

[Voss]

F = 100000;
for i = 1:30
    Ct = F*0.04.*ones(i,1);
    Ct(i) = Ct(i)+F
end

Ct = 104000

Ct = 2×1

4000 104000

Ct = 3×1

4000 4000 104000

Ct = 4×1

4000 4000 4000 104000

Ct = 5×1

4000 4000 4000 4000 104000

Ct = 6×1

4000 4000 4000 4000 4000 104000

Ct = 7×1

4000 4000 4000 4000 4000 4000 104000

Ct = 8×1

4000 4000 4000 4000 4000 4000 4000 104000

Ct = 9×1

4000 4000 4000 4000 4000 4000 4000 4000 104000

Ct = 10×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 104000

Ct = 11×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 12×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 13×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 14×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 15×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 16×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 17×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 18×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 19×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 20×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 21×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 22×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 23×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 24×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 25×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 26×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 27×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 28×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 29×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Ct = 30×1

4000 4000 4000 4000 4000 4000 4000 4000 4000 4000

Answer 2

[Bruno Luong]

F = 100000;  
i = 3;
Ct= F*0.04.*ones(1,i);
Ct(end) = Ct(end)+F

Ct = 1×3

4000 4000 104000

[Jd45ter]

This looks good but I need it to calculate it for i = 1:1:30 thanks

[Bruno Luong]

loop on i? You don't know to use for-loop ?

[Jd45ter]

I have tried a for loop, as I stated in the question. But it wasnt getting the correct output.

[Bruno Luong]

Then post your code with for-loop, and please be more precise when asking question.