I would like to pick the consecutive cells those satistfies my given condition

I have a array of 122 by 10 data set. I have given the criteria to pick the cells whose values are greather than equal to 1.

Now I would like to pick the cells which satisfies the above condition and those satisfies cells are consecutively aranged.

For Ex: Cell 25,26,27,31 are satisfiying the above creiteria . But I wanted to highligh or list out the greter than or equal to 3 consecutive cells, which mean it has to highlight cell25,26,27

[Matt J]

Consecutively along columns? And, to be clear, when you say "cell" you don't really mean a cell array, right?

Answer 1

[Matt J]

You might benefit from downloading,

https://www.mathworks.com/matlabcentral/fileexchange/78008-tools-for-processing-consecutive-repetitions-in-vectors

Then you can label consecutive groups of true elements with, e.g.,

a=rand(1,10)+randi([0,1],1,10)

a = 1×10

0.0060 1.1285 1.2700 0.9325 0.1607 0.3040 0.0583 1.7232 0.4577 1.9700

G=groupTrue(a>1)

G = 1×10

0 1 1 0 0 0 0 2 0 3

[Poorna Durga Geesupalli]

Dear matt,

Thank you, it works .

Here my doubt is can I able to pick those group whose length is greter than 3 alone.

[Image Analyst]

You can use bwareaopen

G =  [0     1     1     0     0     0     0     2     0     3 0 4 4 4 4  0 5 5 5]

G = 1×19

0 1 1 0 0 0 0 2 0 3 0 4 4 4 4 0 5 5 5

longerThan3 = bwareaopen(G, 3)

longerThan3 = 1×19 logical array
   0   0   0   0   0   0   0   0   0   0   0   1   1   1   1   0   1   1   1

[Matt J]

Or, you can use groupLims from the same File Exchange package, and which doesn't require the Image Processing Toolbox.

G =  [1     1        0     0     2     0     3 0 4 4 4 4  0 5 5 5]

G = 1×16

1 1 0 0 2 0 3 0 4 4 4 4 0 5 5 5

[~,~,runlengths]=groupLims(G,1);

G(logical(G))=runlengths(nonzeros(G));

G=groupTrue(G>=3)

G = 1×16

0 0 0 0 0 0 0 0 1 1 1 1 0 2 2 2

[Poorna Durga Geesupalli]

Dear Matt,

Thank you very much it works well

[Poorna Durga Geesupalli]

Dear Matt,

How can we group multiple conditions ???

For example X=[-1.19 -0.94 -0.78 -0.47 -0.28 -0.22 1.05 1.23 0.78 1.55 1.45 1.00];

From this data I have grouped the values which is >=1 and <=-0.5.

Now I would like to group these two criterias besides a new criteria.

Like wise: Condition 1: I have to get a group where the values <=-0.5 values are more than 3 or= consecutive

Condition 2: Group the cells which values are >=1 more than or = 3 consecutive cells

Condition 3: Group the cells which satisfies the above two criteria in between them.

Answers for each condition:

Condition1: GrpA=[-1.19 -0.94 -0.78]

Condition 2: GrpB=[1.55 1.45 1.00];

Condition 3: GrpC=[ -0.47 -0.28 -0.22 1.05 1.23 0.78];

I want my answer like this :

Tirads =[GrpA GrpC GrpB];

Triadlength=[3 6 3];

Now my function has to pick the above Triads

Can we do this ???

[Matt J]

Why wouldn't GrpA be,

X=[-1.19  -0.94  -0.78  -0.47  -0.28  -0.22  1.05  1.23  0.78  1.55  1.45  1.00];

GrpA=X(X<=0.5)

GrpA = 1×6

-1.1900 -0.9400 -0.7800 -0.4700 -0.2800 -0.2200

[Poorna Durga Geesupalli]

The Group A criteria is to pick the cells whose values are <= -0.5 and those cells are consecutively arranged.

The above criteria X(X<=-0.5) is picking up wrong values.

[Matt J]

How is it wrong? The 6 elements that it returns are indeed consecutively arranged in X.

X=[-1.19  -0.94  -0.78  -0.47  -0.28  -0.22  1.05  1.23  0.78  1.55  1.45  1.00];

X(1:6)<=0.5

ans = 1×6 logical array
   1   1   1   1   1   1

[Poorna Durga Geesupalli]

It has to pick the values <=-0.5

The above code is picking the values -0.28 -0.22 too.