# Reshape Nx1 struct with field of Mx1 elements to N*Mx1 vector

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Sabyrzhan Tasbolatov il 22 Mag 2022
Commentato: Stephen23 il 22 Mag 2022
I have a struct A of [1000x1] size. There is a field "bar" which has [100x1] elements.
I want to have 1 variable, let's say B, which will be [1000*100x1] of "bar" elements.
How can I do it without iterating a struct and appending on some prepared zeroed vector? Can reshape do it?
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Stephen23 il 22 Mag 2022
"How can I do it without iterating a struct and appending on some prepared zeroed vector? Can reshape do it?!
No, but a comma-separated list can do it:

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### Risposta accettata

Bruno Luong il 22 Mag 2022
Modificato: Bruno Luong il 22 Mag 2022
Something like
B = cat(1,A.bar)
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### Più risposte (1)

MJFcoNaN il 22 Mag 2022
This is an example:
bar=rand(100,1)
bar = 100×1
0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464
A=struct;
A.bar=bar;
% copy A.bar to all 1000 elements
A(2:1000,1)=A(1)
A = 1000×1 struct array with fields:
bar
% table is a good intermediate form
tbl=struct2table(A);
B=cell2mat(cellfun(@transpose, tbl.bar, 'UniformOutput', false))
B = 1000×100
0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013
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Sabyrzhan Tasbolatov il 22 Mag 2022
Thanks, I'm going to use cat as it's faster
Elapsed time is 0.001430 seconds.
I've also tried your option, it takes:
Elapsed time is 0.020119 seconds.

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