Why am I getting syntax

dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
I dont know where i go wrong. I keep on getting syntax parentheses error.

Risposte (1)

Benjamin Thompson
Benjamin Thompson il 13 Giu 2022

0 voti

Missing two closing parenthesis it would appear. Is MATLAB suggestion not correct? You might do better breaking this up into multiple lines using the ... operator notation for easier readability.
>> dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.
Did you mean:
>> dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+eps.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+eps.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+eps.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+eps.*X)))+(db.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+eps.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+eps.*X)))).^2)));

Categorie

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by