Is it possible to get the path of a file using uigetfile() ?

10 visualizzazioni (ultimi 30 giorni)
What I want to do is get the path of a file that user selects, lets say an image is in downloads folder (example: 'C:\Users\%UserName%\Downloads\image.png').
So when executing the script the path of file is saved in a string and showed in command window.
Right now I have no succes with the following, I'm I using the correct functions for this?
filepath = fileparts( uigetfile() );
disp(['This is the file path: ',filepath]);

Risposta accettata

Walter Roberson
Walter Roberson il 23 Giu 2022
[filename, filepath] = uigetfile();
if ~ischar(filename); return; end %user cancel
fullname = fullfile(filepath, filename);
fprintf('This is the file path: %s\n', fullname);

Più risposte (0)

Categorie

Scopri di più su Environment and Settings in Help Center e File Exchange

Prodotti


Release

R2015a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by