Unable to convert the following expression into double array

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chaaru datta il 24 Giu 2022

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https://it.mathworks.com/matlabcentral/answers/1747050-unable-to-convert-the-following-expression-into-double-array

Commentato: chaaru datta il 25 Giu 2022

Hello all, When I run my code, I keep getting this error: "Unable to convert expression containing remaining symbolic function calls into double array. Argument must be expression that evaluates to number."

clc;
clear all;
close all;
al = 0.5; 
n = 5; 
sig2_fsnrn = 1; 
sig2_ksln = 1; 
sig2_glnrn = 10; 
sig2_e_fsnrn = 0;
sig2_e_ksln= 0; 
sig2_e_glnrn =0; 
L = 1;
Nr = 1; 
gamma_th_dB = 3;
gamma_th = (10^(gamma_th_dB/10));
 vel_r =0; 
 c = 3*10^8; 
 fc = 915*10^6; 
 Rs = 9.6*10^3; 
 Z1 = ((2*pi*fc*vel_r)/(Rs*c)); 
 P_fsnrn = besselj(0,Z1); 
 P_ksln = besselj(0,Z1);
 P_glnrn = besselj(0,Z1); 
 
 v_phi_fsnrn = (1-P_fsnrn^(2*(n-1)))*sig2_fsnrn; 
 v_phi_ksln = (1-P_ksln^(2*(n-1)))*sig2_ksln; 
 v_phi_glnrn  = (1-P_glnrn ^(2*(n-1)))*sig2_glnrn ;
 
 rho2_fsnrn = (P_fsnrn)^(2*(n-1));
 rho2_ksln = (P_ksln)^(2*(n-1));
 rho2_glnrn = (P_glnrn)^(2*(n-1));
 
 
  OP_th = [];
  
  for j1 = -5:5:45 
     jj1 = 10^(j1/10); 
     jj1
        
     
      mu4_1 = (al^2)*v_phi_glnrn*(v_phi_ksln + (rho2_ksln*sig2_e_ksln));
      mu4_2 = (al^2)*rho2_glnrn*sig2_e_glnrn*(v_phi_ksln + (rho2_ksln*sig2_e_ksln));
      mu4_3 =  v_phi_fsnrn+(rho2_fsnrn*sig2_e_fsnrn+(1/jj1));
      mu4 = mu4_1+mu4_2+mu4_3;
      
      zeta = (al^2)*rho2_glnrn*rho2_ksln;
      mu1 = (al^2)*rho2_glnrn*(v_phi_ksln + (rho2_ksln*sig2_e_ksln));
      mu2 = (al^2)*rho2_ksln*(v_phi_glnrn + (rho2_glnrn*sig2_e_glnrn));
      mu3 = rho2_fsnrn;
     
       syms x1;
     part1 = exp((gamma_th*mu2*x1)/((zeta*x1-mu1)*sig2_glnrn));
     part2 = exp((gamma_th*mu4)/((zeta*x1-mu1)*sig2_glnrn));
     part3 = exp(-x1/sig2_ksln);
     part4_1 = (-1/sig2_fsnrn);
     part4_2 = (gamma_th*mu3)/((zeta*x1-mu1)*sig2_glnrn);
     part4 = -1/(part4_1+part4_2);
     
     pt_1 = part1*part2*part3*part4;
     I1 = int(pt_1,0,10);
     op_th1 = (1/(sig2_ksln*sig2_fsnrn))*I1;
     op_th = 1-op_th1;
     OP_th = [OP_th,op_th];            
  end
  SNRdB = -5:5:45; 
grid on;
semilogy(SNRdB,OP_th,'g-','LineWidth',1.1);

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chaaru datta il 24 Giu 2022

Thanks for your answer sir. It means MATLAB is unable to solve the integration. So does it mean that we cannot plot this expression in MATLAB.

KSSV il 24 Giu 2022

In a way yes.....try to find out the integration of the expression. Or read tips to see whether integration can be solved in matlab.

Accedi per commentare.

Accedi per rispondere a questa domanda.

Answer 1

Torsten il 24 Giu 2022

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https://it.mathworks.com/matlabcentral/answers/1747050-unable-to-convert-the-following-expression-into-double-array#answer_992570

Modificato: Torsten il 24 Giu 2022

Apri in MATLAB Online

clc;

clear all;

close all;

al = 0.5;

n = 5;

sig2_fsnrn = 1;

sig2_ksln = 1;

sig2_glnrn = 10;

sig2_e_fsnrn = 0;

sig2_e_ksln= 0;

sig2_e_glnrn =0;

L = 1;

Nr = 1;

gamma_th_dB = 3;

gamma_th = (10^(gamma_th_dB/10));

vel_r =0;

c = 3*10^8;

fc = 915*10^6;

Rs = 9.6*10^3;

Z1 = ((2*pi*fc*vel_r)/(Rs*c));

P_fsnrn = besselj(0,Z1);

P_ksln = besselj(0,Z1);

P_glnrn = besselj(0,Z1);

v_phi_fsnrn = (1-P_fsnrn^(2*(n-1)))*sig2_fsnrn;

v_phi_ksln = (1-P_ksln^(2*(n-1)))*sig2_ksln;

v_phi_glnrn = (1-P_glnrn ^(2*(n-1)))*sig2_glnrn ;

rho2_fsnrn = (P_fsnrn)^(2*(n-1));

rho2_ksln = (P_ksln)^(2*(n-1));

rho2_glnrn = (P_glnrn)^(2*(n-1));

OP_th = [];

for j1 = -5:5:45

jj1 = 10^(j1/10);

%jj1

mu4_1 = (al^2)*v_phi_glnrn*(v_phi_ksln + (rho2_ksln*sig2_e_ksln));

mu4_2 = (al^2)*rho2_glnrn*sig2_e_glnrn*(v_phi_ksln + (rho2_ksln*sig2_e_ksln));

mu4_3 = v_phi_fsnrn+(rho2_fsnrn*sig2_e_fsnrn+(1/jj1));

mu4 = mu4_1+mu4_2+mu4_3;

zeta = (al^2)*rho2_glnrn*rho2_ksln;

mu1 = (al^2)*rho2_glnrn*(v_phi_ksln + (rho2_ksln*sig2_e_ksln));

mu2 = (al^2)*rho2_ksln*(v_phi_glnrn + (rho2_glnrn*sig2_e_glnrn));

mu3 = rho2_fsnrn;

%syms x1;

part1 = @(x1)exp((gamma_th*mu2*x1)./((zeta*x1-mu1)*sig2_glnrn));

part2 = @(x1)exp((gamma_th*mu4)./((zeta*x1-mu1)*sig2_glnrn));

part3 = @(x1)exp(-x1/sig2_ksln);

part4_1 = (-1/sig2_fsnrn);

part4_2 = @(x1)(gamma_th*mu3)./((zeta*x1-mu1)*sig2_glnrn);

part4 =@(x1) -1./(part4_1+part4_2(x1));

pt_1 = @(x1)part1(x1).*part2(x1).*part3(x1).*part4(x1);

I1 = integral(pt_1,0,10)

op_th1 = (1/(sig2_ksln*sig2_fsnrn))*I1;

op_th = 1-op_th1;

OP_th = [OP_th,op_th];

end