What is result of x = min(A(:));

I am looking at result of a program and value result do not look right Looking at code ( can't run test to check right now)

If (min(e(:) <= 5)
   Z = 1
Else
   Z=0
End

Answer seem to set a=0 There are 26 elements in the array with a value <= 5 So I am wondering is if the results z is 26 or is it equal the lowest value in the array?

[Stephen23]

This results in an error actually, due to unmatched parentheses in the first line: (min(e(:) <= 5). Until you show us exactly where the parentheses are, any answer is going to be meaningless.

Answer 1

[Alex Taylor]

The result of

A = [4 5; 8 7];
x = min(A(:))

is:

x =

     4

This is because any matrix in MATLAB can be linearly indexed from 1 to the total number of elements in the matrix. So, the operation A(:) reshapes A into an Nx1 vector, then the min operation scans from the first element to the last element of the N element vector ooking for the minimum.

Answer 2

[Scott Webster]

Not sure if part of your confusion is your "order of operations" i.e. the difference between min(e)<5 and min(e<5)... Here is some demo code...

>> A=1:5

A =

       1     2     3     4     5

>> min(A)

ans =

       1

>> A<=3

ans =

       1     1     1     0     0

>> min(A<=3)

ans =

       0

>>