Comparing Rows of Char Array to String
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Hi everyone,
I have an 8x3 char array that looks like the following
Wed
Wed
Wed
Wed
Wed
Wed
Wed
Sat
I need to compare it to a string to perform one action when the day is Wednesday (or Wed) and a different action when the day is Saturday (or Sat). For i = 1:8, a loop runs to put the output of this if statement into a numeric vector.
How can I go about properly comparing each row of the char array to a string ('Wed' or 'Sat')?
Thanks in advance!
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Guillaume
il 11 Feb 2015
c = ['Wed'; 'Wed'; 'Fri'; 'Wed'; 'Sat'];
[~, actionnumber] = ismember(c, ['Wed'; 'Sat'], 'rows')
4 Commenti
Image Analyst
il 11 Feb 2015
Even more robustness can be gained by casting the day to lower case if you don't really care about the case of the letters. Or you could use strcmpi(). If you don't care about case then it's most robust if your code works regardless if they capitalized the day or not.
if strcmp(lower(dayname(i, :)), 'wed')
if strcmpi(dayname(i, :), 'Wed')
switch lower(dayname(i, :))
case 'wed'
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