how to plot hexagon inside boundary?

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Sierra
Sierra on 10 Aug 2022
Commented: dpb on 16 Aug 2022
I have boundary coordinates and I want to fill the patch with hexagons just like honeycomb.
Pleast let me know how to do this.
Thanks

Accepted Answer

dpb
dpb on 11 Aug 2022
As a starting point...
N=6;
t=2*pi*(1/(2*N):1/N:1).';
x=cos(t);y=sin(t);
fill(x,y,'k')
axis square
hold on
hH=fill(x+2*max(x),y,'r');
axis square
ylim(xlim)
Those on the same row are obvious, the fillers in between need an adjustment of the x positon of only 1*x and of the height of the vertical side for y for the initial point -- then it's also tiled by 2X the X,Y position.
<fill> has a builtin replication routine that, I think, can be used to build the full array automagically, but I've not dug into just how to use it/how it works; there's not an example and didn't have time(*) to dig at the moment.
(*) Well, more like "inclination" would be more accurate... :)
  2 Comments
dpb
dpb on 16 Aug 2022
I don't have the mapping toolbox to even try, sorry...all I know is what I showed before of how to generate the coordinates of a hexagon and offset set them one to another to tile them...

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