Azzera filtri
Azzera filtri

What to change in code?

3 visualizzazioni (ultimi 30 giorni)
Steve
Steve il 10 Ott 2011
Hello Experts,
Given the following code:
How to transform it to work with the full polynomial, not from a(1).
I really need someone to help me with this issue urgently.
Thanks in advance!
  3 Commenti
bym
bym il 10 Ott 2011
whats wrong with answers here? http://www.mathworks.com/matlabcentral/answers/17931-bairstow-method-to-find-polynomial-roots-matlab-code-problem
Steve
Steve il 10 Ott 2011
Hello proecsm,
Thanks for commenting, I am going to publish the problem and what I have done, so please be so kind and help me.

Accedi per commentare.

Risposte (1)

Wayne King
Wayne King il 10 Ott 2011
Steve, I have the same question proecsm asks, what's wrong with the answer Walter and I gave you in your earlier post? If you want the roots of:
p(x) = 2*x^2+2*x+1
You can do that with
roots([2 2 1])
or using your function, simply divide through by 2 and don't include the leading 1.
[rts,it]=bairstow([1 1/2],2,1e-3);
As I read Walter's post that is exactly what he clearly explained to you. And I certainly tried to explain very much the same thing.
It seems to me that you're much better off learning to provide the correct input to the funtion you have instead of trying to modify it to accept the input you want to give it.
  1 Commento
Walter Roberson
Walter Roberson il 10 Ott 2011
Yup, exactly.
if a(1) ~= 1; a = a ./ a(1); end
a = a(2:end);
The test for 1 is merely an optimization. You could just use
a = a(2:end) ./ a(1);

Accedi per commentare.

Categorie

Scopri di più su Introduction to Installation and Licensing in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by