logic question regarding two vectors

The two vectors, x=[0, -4, 7, 0, -1, 2], y=[1, -4, 8, 0, 1, 6] are given. Explain how matlab could reutrn...z = x and (not y)

[Stephen23]

https://web.archive.org/web/20220908202328/https://www.mathworks.com/matlabcentral/answers/1800900-logic-question-regarding-two-vectors

Answer 1

[David Hill]

Really have no idea what you are asking.... just guessing

x=[0, -4, 7, 0, -1, 2];
y=[1, -4, 8, 0, 1, 6];
z=min(x,y)

z = 1×6

0 -4 7 0 -1 2

[Sami Ahmed]

im not understanding this HW question ...

[David Hill]

x=[0, -4, 7, 0, -1, 2];
y=[1, -4, 8, 0, 1, 6];
z=x&~y

z = 1×6 logical array
   0   0   0   0   0   0

z=(x&y)|(~x)

z = 1×6 logical array
   1   1   1   1   1   1

Note, x and y vectors can be converted to logical vectors: anynumbers not zero are logical 1, otherwise logical zero

logical(x)

ans = 1×6 logical array
   0   1   1   0   1   1

logical(y)

ans = 1×6 logical array
   1   1   1   0   1   1

[Walter Roberson]

@David Hill

This was obviously a homework question though...

[Sami Ahmed]

okay...?

[Sami Ahmed]

@David Hill thank you

[Walter Roberson]

@Sami Ahmed

We discourage volunteers from giving complete code for homework questions, as we find that when we do that, often the people do not learn the techniques, and instead mostly copy the answer given. We encourage the volunteers to instead answer in ways that teach the concepts, leaving the people asking the questions to apply the concepts to arrive at the answer.

[Sami Ahmed]

i understand, ur like a TA then. I will try to rephrase my questions better.

[Sami Ahmed]

@David Hill @Walter Roberson i was entering z=x&~=y instead of z=x&~y. this was my isse thank you

Answer 2

[Walter Roberson]

The "or" operation for vectors is written as the | operator.

The "and" operation for vectors is written as the & operator.

The "not" operation for vectors is written as the ~ operator.

Note that for the purpose of MATLAB, a value is considered true if it is non-zero (except that it is an error to apply logical tests directly to NaN values.)