How to generate a specific number of values within a range ?

Hi all!

I'm really wondering how to solve this problem: I have an initial matrix Q (100*60), I extracted the first and second non-zero values in each row using this command line

R = size(Q,1);
First_second_ele = zeros(R,2);
for k = 1:R
    tmp = nonzeros(qm(k,:));       %extraction first and second  element
    idx = 1:min(2,numel(tmp));
    First_second_ele(k,idx) = tmp(idx);
    
end

after this , i got two column vectors. Now i want to see 60 elements between the two extracted values.

for example the first two element are :

4.0000    5.3333

i used :

A=linspace(4.0000,5.3333,60);

the result :

A = 4.0000 4.0226 4.0452 4.0678 4.0904 4.1130 4.1356 4.1582 4.1808 4.2034 4.2260 4.2486 4.2712 4.2938 4.3164 4.3390 4.3616 4.3842 4.4068 4.4294 4.4520 4.4746 4.4972 4.5198 4.5424 4.5650 4.5876 4.6102 4.6328 4.6554 4.6779 4.7005 4.7231 4.7457 4.7683 4.7909 4.8135 4.8361 4.8587 4.8813 4.9039 4.9265 4.9491 4.9717 4.9943 5.0169 5.0395 5.0621 5.0847 5.1073 5.1299 5.1525 5.1751 5.1977 5.2203 5.2429 5.2655 5.2881 5.3107 5.3333

How can i do a loop to get the result of all rows?

[Image Analyst]

Do you want the 60 values to be linearly spaced, or randomly spaced. Not sure what "the result of all rows" is, but you can access each element in A in a for loop like this

for k = 1 : numel(A)
    thisAValue = A(k);
    % Now do something with thisAValue.
end

Or do you want to interpolate with interp1 to get values of your other array between the two values and then insert those 60 new values into your existing Q matrix somewhere?

[Majid]

@Image Analyst Hi! the example above is for the first row , i want to do the same for 100 rows, i can't put in each time the two values in "linspace " function.

the result required is new matrix(100,60)

each row contains the 60 elements (not randomly)between the two extracted values as i gave you the first one.

Answer 1

[Jan]

R = size(Q,1);
First_second_ele = zeros(R,2);
Y = zeros(R, 60);
for k = 1:R
    tmp = nonzeros(qm(k,:));       %extraction first and second  element
    idx = 1:min(2,numel(tmp));
    First_second_ele(k,idx) = tmp(idx);
    if numel(idx) == 2
        Y(k, :) = linspace(tmp(1), tmp(2), 60);
    end
end

[Majid]

@Jan perfect! thank you!

Answer 2

[David Hill]

a=sort(rand(10,2),2);
A=[];
for k=1:size(a,1)
    A=[A;linspace(a(k,1),a(k,2),60)];
end