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Skipping certain lines using fscanf

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Venkata Praneeth
Venkata Praneeth il 20 Set 2022
Modificato: Stephen23 il 20 Set 2022
I have a text file as below and i want to read only the highlighted ones from the text.
I tried using below code, but the scanning stops as it encounters "xmin"- is there any way i can work around this and i should strictly use fscanf or fgetl functions only. Attached text file for reference.
A=fscanf(fid, '%f %f %*s %*f',[2,inf])';

Risposte (3)

Walter Roberson
Walter Roberson il 20 Set 2022
Can it be done using fscanf(). Yes. But that doesn't mean that fscanf() is a good tool for the job.
S = "-4 -7.6 Point 1" + newline + "4 -36.4 Point 5" + newline + "1 xmin" + newline + "3 xmax"
S =
"-4 -7.6 Point 1 4 -36.4 Point 5 1 xmin 3 xmax"
values = sscanf(S, '%f%[^\n]%c', [1 inf]);
lengths = diff([0, find(values == newline), length(values)]);
split_values = mat2cell(values, 1, lengths);
lead_number = cellfun(@(V) V(1), split_values)
lead_number = 1×4
-4 4 1 3
following_text = cellfun(@(V) char(V(2:end)), split_values, 'uniform', 0);
following_text = cellfun(@(str) str(~ismember(str, [10 13])), following_text, 'uniform', 0)
following_text = 1×4 cell array
{' -7.6 Point 1'} {' -36.4 Point 5'} {' xmin'} {' xmax'}
second_number = cellfun(@(str) sscanf(str, '%f%*[^\n]'), following_text, 'uniform', 0)
second_number = 1×4 cell array
{[-7.6000]} {[-36.4000]} {0×0 double} {0×0 double}
numbers = cellfun(@(n1, n2) [n1, n2], num2cell(lead_number), second_number, 'uniform', 0)
numbers = 1×4 cell array
{[-4 -7.6000]} {[4 -36.4000]} {[1]} {[3]}
So it's done... but it isn't pretty. There are better ways.
  2 Commenti
Venkata Praneeth
Venkata Praneeth il 20 Set 2022
Yes it is quite heavy- what is better alternative for it?
Walter Roberson
Walter Roberson il 20 Set 2022
S = "-4 -7.6 Point 1" + newline + "4 -36.4 Point 5" + newline + "1 xmin" + newline + "3 xmax"
S =
"-4 -7.6 Point 1 4 -36.4 Point 5 1 xmin 3 xmax"
numbers = cellfun(@(str) sscanf(str, '%f', [1 inf]), regexp(S, '^[0-9\.eE\-\+ \t]+', 'match', 'lineanchors'), 'uniform', 0)
numbers = 1×4 cell array
{[-4 -7.6000]} {[4 -36.4000]} {[1]} {[3]}

Accedi per commentare.


Bjorn Gustavsson
Bjorn Gustavsson il 20 Set 2022
For this rather loose file-format specification that you've been given (meaning that in a couple of days, weeks or months it will be arbitrarily extended with lines of some other format that should be parsed somewhat differently. Your teacher might not have told you about this but this is the practical reality. If someone tells you to do this at an early stage of any project brnig a proper loggin ax to the next meeting, explain that some well-specified file-format should be chosen, if anyone argues against that hack the ax hard into the table, send my best whishes.)
For this I'd go about the task something like this:
0, in a loop (check for feof as per usual)
1, Read one line at a time as a string.
2, Put the parsing of the current string in a sequence of sscanf calls and check the error-message from its outputs
[A,COUNT,ERRMSG,NEXTINDEX] = sscanf(curr_line,'%f %f %*s %*f');
and so on for the formats of the other lines,
3, then save the requested results in whatever format desired after each match.
HTH

Stephen23
Stephen23 il 20 Set 2022
Modificato: Stephen23 il 20 Set 2022
C = {};
[fid,msg] = fopen('polydata.txt','rt');
assert(fid>=3,'%s',msg)
while ~feof(fid)
C{end+1} = sscanf(fgetl(fid),'%f',[1,Inf]);
end
fclose(fid);
Imported data:
C{:}
ans = 1×2
-4.0000 -7.6000
ans = 1×2
-2.0000 -17.2000
ans = 1×2
0.2000 9.2000
ans = 1×2
1.0000 -1.6000
ans = 1×2
4.0000 -36.4000
ans = 1
ans = 3
ans = 0.2000
ans = []

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