Plot dynamics of an ODE
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UserCJ
il 21 Set 2022
Commentato: Cris LaPierre
il 22 Set 2022
I have an ODE
and I need to plot
with respect to
and
varying p. Following is the sample plot required.

I managed to draw one plot for
and following is the sample code.
[xi,x] = meshgrid(0:0.001:1,0:0.002:1);
p =1
f2 = @(x,a,b) a*b*(x)./(b-2+x));
f1 = @(x,a,b) a*b*(1-x)./(2*b-x);
rs = @(x1,x2,a,b,p) x1.*f1(x,a,b) - p.*(1-x1).*f2(x,a,b);
figure
contour(x1,2,rs(x1,x2,1,2,1),[0 0]);
Next I added a loop for p as follows:
np = 10;
phi = linspace(0,1,np);
for p = 1:np
f2 = @(x,a,b) a*b*(x)./(b-2+x));
f1 = @(x,a,b) a*b*(1-x)./(2*b-x);
rs = @(x1,x2,a,b,p) x1.*f1(x,a,b) - p.*(1-x1).*f2(x,a,b);
R = rs(x1,x2,1,2, p(p));
contour(x1,x2,R);
hold on
end
hold off
But, instead of the required ourput of 10 plots in one graph, I get many plots (>10) in my output. Can someone please help me with this?
1 Commento
Cris LaPierre
il 21 Set 2022
Modificato: Cris LaPierre
il 21 Set 2022
You have not copied your code correctly here, as both examples do not run.
Risposta accettata
Cris LaPierre
il 21 Set 2022
I'm assuming your goal is to plot a line for when the function rs is equal to zero for various values of p. You could do that using contour, but I don't think that is the best way. However, you could still use contour to get the (x,y) coordinates of the 0 contour line for each, and then plot those.
np = 10;
[x1,x2] = meshgrid(0:0.001:1,0:0.002:1);
for p = 1:np
f2 = @(x,a,b) a*b*(x)./(b-2+x);
f1 = @(x,a,b) a*b*(1-x)./(2*b-x);
rs = @(xi,x,a,b,p) xi.*f1(x,a,b) - p.*(1-xi).*f2(x,a,b);
R = rs(x1,x2,1,2, p);
figure(1)
M=contour(x1,x2,R,[0 0]);
figure(2)
plot(M(1,2:end),M(2,2:end),'DisplayName',"p="+p)
axis([0 1 0 1])
hold on
end
hold off
legend(Location="northwest")
4 Commenti
Cris LaPierre
il 22 Set 2022
I would keep the meshgrid approach. That will be faster than looping.
I'm not sure of a best way, but one way to do this without contour is to look for the min(abs(R)) in each row. This won't be the exact zero point, but will be close enough for the visualization.
np = 10;
X = 0.001:0.001:1;
Y = 0.002:0.002:1;
[x1,x2] = meshgrid(X,Y);
for p = 1:np
f2 = @(x,a,b) a*b*(x)./(b-2+x);
f1 = @(x,a,b) a*b*(1-x)./(2*b-x);
rs = @(xi,x,a,b,p) xi.*f1(x,a,b) - p.*(1-xi).*f2(x,a,b);
R = rs(x1,x2,1,2, p);
[xval,xind] = min(abs(R),[],2);
X_z0(:,p) = X(xind);
end
plot(X_z0,Y)
axis([0 1 0 1])
legend(Location="northwest")
Cris LaPierre
il 22 Set 2022
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