how to remove repeating rows from a matrix?(there is a case)

I want to combine all the possible no-repeating permutations of two or more 0,1 row vectors, for example, there are a=[1,0], b=[1,1,0], the combination of all their possible no-repeating permutations will be

     0     1     0     1     1
     0     1     1     0     1
     0     1     1     1     0
     1     0     0     1     1
     1     0     1     0     1
     1     0     1     1     0
I use the following script to ahieve this,
a=[1,0];
b=[1,1,0];
A=perms(a);  %all the possible permutations, may contain repeating rows
B=perms(b);
[r_a,c_a]=size(A); 
[r_b,c_b]=size(B); 
AB=[];
for i=1:r_a
    for j=1:r_b
        COM1=[A(i,:) B(j,:)]; %combine ith rows in A with all rows in B
        D1(j,1:c_a+c_b)=COM1; 
    end
    AB=cat(1,AB,D1); %update AB on every ith loop
end
AB=unique(AB,'rows'); %delete repeating rows
%     AB=union(AB,AB,'rows'); %union can also be used to delete repeating rows

but,in my real case, there are

a=[1,1,0,0,0];

b=[1,1,1,1,0,0];

c=[1,1,1,1,0,0,0];

d=[1,1,1,0,0];

e=[1,1,0,0];

I want to combine all the the possible no-repeating permutations(the result will be ABCDE), using method like the above script,

A=perms(a);

B=perms(b);

C=perms(c);

D=perms(d);

E=perms(e);

and then,

Step 1, combine A and B, delete repeating rows, and result in AB;

Step 2, combine AB and C, delete repeating rows, and result in ABC;

Step 3, combine ABC and D, delete repeating rows, and result in ABCD;

Step 4, combine ABCD and E, delete repeating rows, and result in ABCDE;

but using my method(either using "union" or "unique" to delete), when it comes to Step 4, it is out of memory,

Elapsed time is 1.452821 seconds.%Step 1 Elapsed time is 19.556511 seconds.%Step 2 Elapsed time is 456.368700 seconds.%Step 3 ??? Out of memory. Type HELP MEMORY for your options.

Error in ==> unique at 201 d = b(1:rows-1,:)~=b(2:rows,:);

Error in ==> combine_perms_5 at 85 ABCDE=unique(ABCDE,'rows');%here, I use unique

my questions are,

Q1 Are there simple ways to combine all the possible no-repeating permutations of a,b,c,d,e?

Q2 Are there simple ways to delete repeating rows, making sure that it is not out of memory?

I really appreciate your comment on this!

Answer 1

[Andrei Bobrov]

A = perms([0 0 1 1 1]);
AB=unique(A(sum(A(:,1:2),2)==1 | sum(A(:,3:end),2)==2,:),'rows');

variant

a=[1,1,0,0,0];
b=[1,1,1,1,0,0];
c=[1,1,1,1,0,0,0];
d=[1,1,1,0,0];
e=[1,1,0,0];
Din = {a b c d e};
d = cellfun(@(x)unique(perms(x),'rows'),Din,'un',0);
ns = cellfun('size',d,1);
inarg = arrayfun(@(i1)1:i1,ns,'un',0);
M = cell(1,numel(Din));
[M{:}] = ndgrid(inarg{:});
outc = cellfun(@(x,y)x(y(:),:),d,M,'un',0);
out = [outc{:}];

solution on my computer (HP Compaq dx2400 Microtower IntelC2D 2.13GHz, RAM 2GB)

[Zhang]

It works, thx indeed! another question, I run the script and the result variable "out" in workspace is an 315000*27 double variable, but "Min"and "Max" shows"Too many elements", I run max(out) and min(out), it shows,

>> max(out)

ans =

Columns 1 through 11

1 1 1 1 1 1 1 1 1 1 1

Columns 12 through 22

1 1 1 1 1 1 1 1 1 1 1

Columns 23 through 27

1 1 1 1 1

>> min(out)

ans =

Columns 1 through 11

0 0 0 0 0 0 0 0 0 0 0

Columns 12 through 22

0 0 0 0 0 0 0 0 0 0 0

Columns 23 through 27

0 0 0 0 0

how can it be all 1 or all 0 in "out"?