MATLAB欧式距离的代码优化。

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Risposto: 埃博拉酱 il 23 Nov 2024 alle 1:41
point = [1 2 3 4 5 6,,,,,n;2 4 3 5 ,,,,,n;.......;128 ,,,,,, ];(point是一个非常大的矩阵:128*n)
dis = [];
tem = [];
for i = 1:length(point)-1
for j = i+1:length(point)
distemp = pdist([alldesc(:,i)';alldesc(:,j)']);
tem = [i j distemp];
dis = [dis;tem];
end
end
简单描述就是:计算矩阵的每一列与其他列的pdist,然后保存数据,可是当point非常大的时候,计算就非常慢,所以想知道有没有更高效的写法

Risposte (1)

埃博拉酱
埃博拉酱 il 23 Nov 2024 alle 1:41
[dis(:,1),dis(:,2)]=find(tril(true(width(alldesc)),-1));
dis(:,3)=pdist(alldesc.');

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