How does the cycle for , if work?

Dear All, I have n=[0:1:10] and the column K=[-2,5,-5]. I would like to generate a cycle in which each time It takes an item of n and adds it to K, every time It checks if the sum(K) is zero: if it is zero it must write the value of "n".

I wrote this but it doesn't work:

for n=0:1:10

    K=[-2,5,-5];
    Z=K+n;
    S=sum(Z);
    if S==0
        n
    end
end
Could you help me, please.
Thanks in advance
Best regards

Massimo

Answer 1

[Adam]

K=[-2,5,-5];
n = 0:10'

res = bsxfun( @plus, K, n' );
resSum = sum( res, 2 );
zeroSums = resSum == 0;
n( zeroSums )

should give you the result you want without needing a loop, if I understand your requirements correctly.

[massi]

thank you massi

Answer 2

[James Tursa]

The reason it doesn't produce any output is because the sum is never 0. E.g., print out S each iteration to see what is going on:

for n=0:1:10
    K=[-2,5,-5];
    Z=K+n;
    S=sum(Z);
    disp(S);
    if S==0
        n
    end
end

If you think the sum should have been 0 at some point, then you need to re-examine your algorithm and the problem you are solving.

[massi]

ok thanks massi