Azzera filtri
Azzera filtri

Relocate element from a row to another

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Giannakis Stoukas
Giannakis Stoukas il 21 Mar 2015
Modificato: dpb il 22 Mar 2015
Hello,i want to relocate an element from a row to an another and delete the other row.For example i have the matrix
A=[1 2 4 8 3 1;
1 9 7 6 1 ;
1 5 1 ]
and i want to relocate the 5 so i will have the matrix
A=[1 2 4 8 3 1;
1 9 7 5 6 1]
  7 Commenti
the cyclist
the cyclist il 22 Mar 2015
It's not possible to understand the rule you want to follow, from the one example you give.
Giannakis Stoukas
Giannakis Stoukas il 22 Mar 2015
Actually it is a problem of local search algorithm,and it is too complicated it explain it from here. I just wanted the orders to move the element 5 between 7 and 6,and move all the other elements one position right.The rule to delete a row is "if the row has only zeros or ones,delete it",and i want the orders to do it.I know i am not very comprehensible,but it is a bit complicated to explain all the theory.

Accedi per commentare.

Risposte (2)

the cyclist
the cyclist il 22 Mar 2015
A=[1 2 4 8 3 1;
1 9 7 6 1 0;
1 5 1 0 0 0]
A = [A(1,:);
A(2,1:3) A(3,2) A(2,4:5)]
This is my best guess at what you want.

dpb
dpb il 22 Mar 2015
Modificato: dpb il 22 Mar 2015
Well, it's not possible to write anything except the specific answer without a definition of the logic. Anything else is indiscernible from magic, not science.
But, let's see, addressing the question as asked...
>> id76=sub2ind(size(A'),4,2);
>> id5=sub2ind(size(A'),2,3);
>> B=reshape(A',1,[]);
>> B=reshape([B(1:id76-1) B(id5) B(id76:id5-1) B(id5+1:end)],size(A,2),[]).';
>> B(all(B==0|B==1,2),:)=[]
B =
1 2 4 8 3 1
1 9 7 5 6 1
>>
Needless to say, to make this of much use in general you'll have to have rules to locate the magic numbers used to compute the indices id5 and id76

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