Error using plot Vectors must be the same length.

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LUDMILA
LUDMILA il 14 Nov 2022
Risposto: Jan il 14 Nov 2022
Every time I run this code, I get "Error using plot Vectors must be the same length.
function f = lab_8( x , y)
f = ((x.^2)*cos(y) + 0.1);
end
function [x,y] = lab_8_method_2(f, y0, sp, h)
x = sp(1):h:sp(2);
y = y0;
for n =1:length(x)-1
x(n) = (n-1)*h;
y(n+1) = y(n)+h*(0.75*f(x(n),y(n))+...
0.25*f(x(n)+h/0.5,y(n)+...
(h/0.5)*f(x(n),y(n))));
end
end
function [x,y] = lab_8_method_4(f, y0, sp, h)
x = sp(1):h:sp(2);
y = y0;
for n=1:length(x)-1
k1=f(x(n) , y(n));
k2=f(x(n)+h/2 , y(n)+h*k1/2);
k3=f(x(n)+h/2 , y(n)+h*k2/2);
k4=f(x(n)+h , y(n)+h*k3);
dy= h*(k1+2*k2+2*k3+k4) / 6;
y(n+1) = y(n) + dy;
end
end
[x, y2] = lab_8_method_2(@lab_8, 0.3, [0 1 ], 0.01);
plot(x, y2 ,'r'); hold on;
[x, y4] = lab_8_method_4(@lab_8, 0.3, [0 1], 0.01);
plot(x, y4, 'b'); hold on;
qn = dsolve('Dy = (x.^2)*cos(y) + 0.1', 'y(0) = 0.3');
syms t
v = subs(qn, [t], [x]);
a = eval(v); plot(x,a,'y'); hold off;
legend('2-го порядку', ' 4-го порядку', ' Точна відповідь');
T=table(x(:), y2(:), y4(:), a(:));
T.Properties.variableNames = {'xi','Рунге-Кутта 2-го порядку','Рунге-Кутта 4-го порядку', 'Точна відпоівдь'}
  1 Commento
Image Analyst
Image Analyst il 14 Nov 2022
Please put only one line of code on a line and then highlight your code and click the Code icon to format your code as code so we can read it easily and copy it easily (to run it in MATLAB).

Accedi per commentare.

Risposte (1)

Jan
Jan il 14 Nov 2022
[x, y2] = lab_8_method_2(@lab_8, 0.3, [0 1], 0.01);
plot(x, y2 ,'r'); hold on;
[x, y4] = lab_8_method_4(@lab_8, 0.3, [0 1], 0.01);
plot(x, y4, 'bo'); hold on;
qn = dsolve('Dy = (x.^2)*cos(y) + 0.1', 'y(0) = 0.3');
Warning: Support of character vectors and strings will be removed in a future release. Use sym objects to define differential equations instead.
Consider this warning.
syms t
v = subs(qn, t, x);
a = eval(v);
size(x)
ans = 1×2
1 101
size(a)
ans = 1×2
1 10201
This is the problem. x is a row vector with 101 elements. The equation is defined as CHAR vector. t is symbolic, but you substitute it by a numerical vector. The equation does not contain a "t", but only y and x, so substituting t is not meaningful.
Read the examples of dsolve again and rewrite the symbolic part.
plot(x,a,'y'); hold off;
Error using plot
Vectors must be the same length.
function f = lab_8(x , y)
f = x.^2 * cos(y) + 0.1;
end
function [x,y] = lab_8_method_2(f, y0, sp, h)
x = sp(1):h:sp(2);
y = y0;
for n = 1:length(x)-1
x(n) = (n-1)*h;
y(n+1) = y(n)+h*(0.75*f(x(n),y(n))+...
0.25*f(x(n)+h/0.5,y(n)+...
(h/0.5)*f(x(n),y(n))));
end
end
function [x,y] = lab_8_method_4(f, y0, sp, h)
x = sp(1):h:sp(2);
y = y0;
for n=1:length(x)-1
k1 = f(x(n) , y(n));
k2 = f(x(n)+h/2 , y(n)+h*k1/2);
k3 = f(x(n)+h/2 , y(n)+h*k2/2);
k4 = f(x(n)+h , y(n)+h*k3);
dy = h*(k1+2*k2+2*k3+k4) / 6;
y(n+1) = y(n) + dy;
end
end

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