# Vector form of for loop?

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Sadiq Akbar il 21 Nov 2022
Commentato: Sadiq Akbar il 22 Nov 2022
I have a piece of code that works fine. But it has a for loop as below:
M=5;
N=10;
abc=0.0;
for m1=1:M*N
abc=abc+(abs(yo(m1,1)-ye(m1,1))).^2;
end
abc=abc/(M*N);
e=abc;
What will be its vectored form to reduce the execution time?
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Torsten il 21 Nov 2022
Modificato: Torsten il 21 Nov 2022

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### Risposta accettata

Matt J il 21 Nov 2022
Modificato: Matt J il 21 Nov 2022
e=norm(yo-ye).^2/M/N
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Matt J il 21 Nov 2022
Modificato: Matt J il 21 Nov 2022
Also is it true for any lenght of vector u?
Yes, try it.
can you make me understand on the line:
Perhaps an example,
steerA=randi(5,3,2)
steerA = 3×2
5 4 4 2 5 2
steerB=randi(50,3,2);
%original version
steerM = zeros(size(steerA, 1)*size(steerB, 1), size(steerA,2));
for idxK = 1 : size(steerM,2)
steerM(:, idxK) = kron(steerB(:, idxK), steerA(:, idxK));
end
%new version
steerM2=steerA.*permute(steerB,[3,2,1]);
%compare
steerM,steerM2
steerM = 9×2
30 176 24 88 30 88 160 104 128 52 160 52 160 20 128 10 160 10
steerM2 =
steerM2(:,:,1) = 30 176 24 88 30 88 steerM2(:,:,2) = 160 104 128 52 160 52 steerM2(:,:,3) = 160 20 128 10 160 10
Sadiq Akbar il 22 Nov 2022
Thanks a lot dear Matt J for your kind help.Regards,

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